Subject
- Posted on
December 25, 2007, 11:31 am
According to Anstrom's "Computer controlled system" page 37 paragraph
above example 2.5, in order there is a corresponding continuous
system, the eigenvalue of the state space matrix phi must not have
eigenvalues on the negative real axis, why?
Re: Eigenvalue of Phi in state space must no be negative?
On Tue, 25 Dec 2007 08:31:00 -0800, leaf wrote:
Eigenvalues on the negative real axis in the sampled time domain
correspond to continuous-time eigenvalues with infinite real parts.
That's kind of hard to achieve in practice.
--
Tim Wescott
Control systems and communications consulting
http://www.wescottdesign.com
Need to learn how to apply control theory in your embedded system?
"Applied Control Theory for Embedded Systems" by Tim Wescott
Elsevier/Newnes, http://www.wescottdesign.com/actfes/actfes.html
Re: Eigenvalue of Phi in state space must no be negative?
On Tue, 25 Dec 2007 15:24:54 -0600, Tim Wescott wrote:
I should also mention that there is an uncertainty in the mapping of
eigenvalues back from the z domain to the s domain. The magnitude of the
z-domain eigenvalue maps unambiguously to the s domain, but the polar
angle of the eigenvalue in the z domain maps to an infinite number of
eigenvalues spaced at 2 * pi * sampling frequency apart in the imaginary
direction in the s domain.
So you can take a system description in the z domain and come up with _a_
continuous-time system, maybe, but you can't come up with _the_
continuous-time system without some further constraints on the
eigenvalues.
--
Tim Wescott
Control systems and communications consulting
http://www.wescottdesign.com
Need to learn how to apply control theory in your embedded system?
"Applied Control Theory for Embedded Systems" by Tim Wescott
Elsevier/Newnes, http://www.wescottdesign.com/actfes/actfes.html
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