How to calculate the time delay created by a tube.

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Hi,

I am trying to model a pressure tube of length 'L', where a fan is
attached at one end and the other end is open.
I know that Pressure  in the tube will vary w.r.to space and time when
there is some change in excitation at the input. I got the pressure
drop equation ,

[Pressure drop] dP = 4 f dx V^2 /(gD)

f - friction created by the walls of the tube.
dx - distance.
V - velocity of air flow.
D- diameter of the tube.
g- gravity

Using the above equation, I can calculate pressure drop at any distance
(dp/dx) directly. But how can I  get the time delay created by the
tube.  Please some one guide or teach me how to derive P(x,t).

Thanks
srinivas


Re: How to calculate the time delay created by a tube.



srinivas wrote:

As far as I know the time dependency will be on the order of the speed
of sound within the tube, times it's length.  So unless you're working
with a really long tube, or a really short time span, you'll be OK.

--

Tim Wescott
Wescott Design Services
http://www.wescottdesign.com

Posting from Google?  See http://cfaj.freeshell.org/google/

"Applied Control Theory for Embedded Systems" came out in April.
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Re: How to calculate the time delay created by a tube.



Tim Wescott wrote:


Arg!  No, that can't be right for significant pressure rises.  There's a
differential equation in there involving the fill time of the tube, the
amount of material you're cramming in and the pressure, but I'd have to
actually work to derive it (not to mention learning more fluid dynamics
than I know now).

--

Tim Wescott
Wescott Design Services
http://www.wescottdesign.com

Posting from Google?  See http://cfaj.freeshell.org/google/

"Applied Control Theory for Embedded Systems" came out in April.
See details at http://www.wescottdesign.com/actfes/actfes.html

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