Re: Putting the 'I' in 'PID'

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Hi Peter,


I'm having an algebra brain fart: on page one, I'm looking at the part
where K_i ad K_p are each shown as functions of the plant params and
the desired characteristic equation. I'm assuming that we set DiffCE =
0 to do start out. Then setting s = 0 gets K_i = (lambda)^2 / K*alpha.
How do we get K_p?

Thanks,

Rick

Re: Putting the 'I' in 'PID'




Setting s to 0 has nothing to do with it.  The two characteristic
equations must be equal for all values of s, therefore the
coefficients for each power of s must be the same.

2*lambda=alpha+K*alpha*Kp

See this recent thread because it applies to you too.
How to get PID Padameters for a "lowpass with integrator" process
http://groups.google.com/group/sci.engr.control/browse_frm/thread/49ab4f796=
f72c43a#
Wolfgang just went through the same exercise but his 'plant' or motor
system is doing position control so his transfer function is has an
extra s in the denominator to integrate velocity in to position.
Wolfgang can tune his motor now.  Wolfgang and I finished up his
thread here
because the spammers are running the use groups.
http://www.eng-tips.com/threadminder.cfm?pid=1438

Peter Nachtwey

Re: Putting the 'I' in 'PID'




Ok, got it now.


I'll give it a read.

Thanks for your help,
Rick

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