state space of mutual inductance

No but the application is reasonably obvious using the equation from
wikipedia
http://en.wikipedia.org/wiki/Inductance
V1=L1 dI1/dt+M dI2/dt
V2=L2 dI2/dt+M dI1/dt
Now move the derivatives to the left, and invert the matrix [L1 M, M
L2] to form a block for the A matrix.  Wire the A matrix subsection up
to the other parts of the circuit.  Usually this is obvious but
occasionally you will lower rank results and you will have to project
down to a full rank subspace.
Does this make sense to you?

Ray