OK folks, any Gear Gurus in the audience?
I'm trying to figure out what the outwards thrust would be on a set of differential spider gears under the condition where the axles are locked from rotating; or alternatively if it's easier to envision the outward thrust on them if one axle & carrier are locked & the torque is applied to the other axle, see diagram here-
Specifics- the spider gears have a tooth bevel of 48°, interior bevel of 68°.
The side gears are 23 & 41 respectively.
Yes, I know those don't add up to 90°, Blame Dana. :/
For sake of argument I'll assume there's no friction between the gear teeth.
Anyone able to give ma a pointer on how to figure this out?
Thanks-
H.