Subject
- Posted on
pbasic 2.5 question.
- 03-04-2007
March 4, 2007, 4:03 am
Hello all,
I'm learning PBASIC 2.5 from a book called PROGRAMMING AND CUSTOMIZING
THE BASIC STAMP COMPUTER and I ran into this situation. The following
code produces the output under it:
code----------------------------------------
' {$STAMP BS2}
' {$PBASIC 2.5}
_x VAR Byte
_y VAR Byte
_z VAR Byte
_area VAR Word
_x = 20
_y = 30
B0 = 155
B1 = 220
W2 = B0 + B1
_area = _x*_y 'solve the area
DEBUG "the Area is ", DEC _area, "sq ft."
DEBUG CR, ? B0, ? B1, ? B2, ? W2
END
======================================
OUTPUT:
the Area is 600sq ft.
B0 = 88
B1 = 2
B2 = 20
W2 = 375
=====================================
My questions are:
-why is B1 = 2 when I declared it '220'?
-why is B2 = 20 when I didn't load it with any values?
-W2 is giving me the correct sum, but why are the B variables
displaying strange results?
Thanks,
-Alex
I'm learning PBASIC 2.5 from a book called PROGRAMMING AND CUSTOMIZING
THE BASIC STAMP COMPUTER and I ran into this situation. The following
code produces the output under it:
code----------------------------------------
' {$STAMP BS2}
' {$PBASIC 2.5}
_x VAR Byte
_y VAR Byte
_z VAR Byte
_area VAR Word
_x = 20
_y = 30
B0 = 155
B1 = 220
W2 = B0 + B1
_area = _x*_y 'solve the area
DEBUG "the Area is ", DEC _area, "sq ft."
DEBUG CR, ? B0, ? B1, ? B2, ? W2
END
======================================
OUTPUT:
the Area is 600sq ft.
B0 = 88
B1 = 2
B2 = 20
W2 = 375
=====================================
My questions are:
-why is B1 = 2 when I declared it '220'?
-why is B2 = 20 when I didn't load it with any values?
-W2 is giving me the correct sum, but why are the B variables
displaying strange results?
Thanks,
-Alex
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