Parallel discharge tubes question

Suppose you had two hydrogen discharge tubes hooked up to the same

25kV power source. The field produced inside the first evacuated and then H2 filled tube ,when raised to 20kV,would cause electrons to move to say a steel positively charged anode and to replenish electrons drawn through copper wires to the power source and protons to move to the steel cathode connected to the negative side of the power source in each case and form new hydrogen or other atoms there with electrons pulled from the 25kV power source. The question is how much more power is used to do this with two such tubes over what is used for one such discharge tube? Also once the current starts to move the move the protons and electrons presumably in the 10^-6mm vacuum without collisions and then electrons are moving inside low resistance leads, I should think minimal energy is being used up? If more hydrogen atoms are added to the discharge chamber from the above process and from the H2 source, then the previous discharge would supply the power source electrodes with the previous requisite amount of opposite charge used to provide the field required to break up the first batch.?

To be more specific, 1)The anode in each case is a 5inch diameter 40inch long steel pipe with 5 inch diameter steel plug screwed into the top through which a

1inch diameter metal tube with a needle valve that supplies the hydrogen. A wire lead from this tube is connected to the positive High Voltage source at say +12.5kV 2)This anode pipe is inside a slightly larger diameter cathode pipe which is connected to a steel plate at the top that rests on a glass cylinder of 15 inch diameter. This plate is connected to a -10kV electrode on the power source. The cathode pipe extends downward an inch past the open end of the anode pipe. A perforated steel cathode plug 5.25 inches diameter and 3 inches deep at the circumference but .25 inches deep in the center is screwed into the cathode pipe to within a quarter inch or less of the anode pipe 5 inch diameter opening. The diameter oriented hole in the plug is .25inch by 5.25 inches by .25 inches deep. 3)The bottom of the glass cylinder is a circular steel plate that is an inch or so below the cathode hole and wire lead from this is connected to the -12.5kV electrode of the power source. Thus protons from the ionized H2 are drawn to this plate through the cathode hole that is 5kV above the plate and drawn to bottom plate that is at -12.5kV. There they combine with electrons drawn from the

-12.5kV electrode of the power source. An insulated hole in this bottom steel plate is connected to the vacuum pump.

Reply to
r9ns
Loading thread data ...

PolyTech Forum website is not affiliated with any of the manufacturers or service providers discussed here. All logos and trade names are the property of their respective owners.