This is about the equation: C = I* dT/dE. I've taken Calculus and currently taking Diff EQ. At the moment I understand about applying Diff EQ techniques to turn that equation into a solution for all values of t (time). What does the equation mean in the form it's currently in? I understand the d means "instantaneous", however, I'm use to seeing equations such as: x d/dx and that tells me to differentiate 'x' with respect to x and the answer would be '1' (X^n = n * times X^n-1). Does the capacitor equation state: C = (I * T) d/dE ? if that's the case, the derivative would be 0 and the equation would C = 0. Theoretically it can be said that dT/dE means: (t1-t2) / (E1 - E2). Typically you can say that, but theoretically Calculus should be applied and I'm a bit confused about that equation. The inductor equation is another one that confuses me, however, I'm sure it would make sense once I understand the above.

- posted
15 years ago