Conversion of mm BTDC to degrees BTDC

Many moons ago, I remember doing the same thing. The .8 mm btdc is actually measured at the top of the piston, through the spark plug hole. I had to calculate the degrees based on rod length and stroke. Do you have that info? If so I'll calculate it for you.

I'm going to jump out here and take a stab at this Assumption that the 0.8mm is piston displacement from TDC. Draw a circle that represents the stroke of the engine, the Diameter of the circle is the stroke. Draw a vertical line through the center of the circle. at a point 0.8mm down this diameter line draw a perpendicular line. So now you have a diagram of what your doing. The cord of the circle intersects the circle at the timing point. now do the math.

Crap! I looked closer at the page, an it looks pretty much for Vespas. Greg

Thanks Steve. I know the stroke, but not the rod length. I'll see if I can find it without taking the engine apart.

Thanks Greg, but that calculator won't let me input my motor's dimensions. Somewhere in the code for that calculator is the algorithm I want, but I don't know how to dig it out.

Yes, just put a dial indicator in through the spark plug hole and mark the flywheel at .8mm BTDC... then use the strobe light to verify that the spark is occuring when your marks line up. David

Attachments in text only NGs are a real no-no.

Ted

"David Courtney" wrote in news:c79rfj$1bj63$ snipped-for-privacy@ID-70857.news.uni-berlin.de:

Note on using this method. With any curved surface, there becomes a point before, and after the apex, where the indication movement will be too small to be registered by the indicator. This dead area could be up to a degree or more. Using the indicator, move the crank until the indicator quits moving, and mark the crank. Then roll the crank until the indicator just starts to move and mark the crank again. the middle of these two points is the actual apex.

It is a whole lot easier to go the other way, here are some equations with example data for degrees to mm, bang the equations into your favorite spreadsheet or calculator and work backwards. If you want I'll email you the excel spreadsheet I did this in

9 theta Crank angle before top dead center

0.768589885 DBTDC Displacement below top dead center =RL + S/2 - PPX(theta)

Solving the equations for theta in terms of BTDC is more complicated than I am will to do if there is an easier way.

Carl Boyd

Draw a triangle, with the three corners representing the wrist pin, the rod journal, and the crank centerline. Label the sides as follows:

a=connecting rod b=crank throw c=distance from crank centerline to wrist pin centerline

At TDC c = a + b

at .8mm BTDC c = a + b - .8mm

cos A = ( b^2 + c^2 - a^2 ) / ( 2 bc ) cos B = ( a^2 + c^2 - b^2 ) / ( 2 ac ) cos C = ( a^2 + b^2 - c^2 ) / ( 2 ab )

Given the lengths of the three sides of a triangle, we can find the cosines of the three angles.

Then this follows:

A = arccos[ ( b^2 + c^2 - a2 ) / ( 2 bc ) ] B = arccos[ ( a^2 + c^2 - b2 ) / ( 2 ac ) ] C = arccos[ ( a^2 + b^2 - c2 ) / ( 2 ab ) ]

A is the degrees BTDC.

Enjoy,