I am confused. The nameplate on my hobart cybertig says that at 230V,
it consumes 44 amps.

http://igor.chudov.com/projects/Welding/00-Hobart-CyberTig-Welder/dscf0003.jpg

Absent the power factor number, that means roughly 220

Yet, it is a 28V, 200A welder, which means approximately 6 kW power output.

How can I reconcile these numbers? How can it take in 16 kW and yet only produce 6 kW? That seems awfully wasteful.

I tried to estimate what it would take, assuming more reasonable power efficiency.

It if produces 6 kW and wastes 2 kW as heat, then it would need 8 kW. Estimating amps, 8 kW/220/sqrt(3) = 21 amp.

This is not an idle question for me. I have 3 phase cabling that is capable of conducting 21 amps (combo of a 12 and 10 gauge cables). For 44 amps, I would need to spend big bucks to buy 4-6 flexible cable.

Also, I can easily support 8 kW power consumption after adding an extra idler to my RPC. 16 kW is out of my realm of possibility due to branch circuit capacity and common sense.

Some clarification would be appreciated.

i

http://igor.chudov.com/projects/Welding/00-Hobart-CyberTig-Welder/dscf0003.jpg

***44***sqrt(3) = 16 kW power consumption.Yet, it is a 28V, 200A welder, which means approximately 6 kW power output.

How can I reconcile these numbers? How can it take in 16 kW and yet only produce 6 kW? That seems awfully wasteful.

I tried to estimate what it would take, assuming more reasonable power efficiency.

It if produces 6 kW and wastes 2 kW as heat, then it would need 8 kW. Estimating amps, 8 kW/220/sqrt(3) = 21 amp.

This is not an idle question for me. I have 3 phase cabling that is capable of conducting 21 amps (combo of a 12 and 10 gauge cables). For 44 amps, I would need to spend big bucks to buy 4-6 flexible cable.

Also, I can easily support 8 kW power consumption after adding an extra idler to my RPC. 16 kW is out of my realm of possibility due to branch circuit capacity and common sense.

Some clarification would be appreciated.

i