I just picked up a Hobart 135 and noticed on the schematics that they look like the same welders with different line voltages. Does anyone know if you change the input from 120VAC to 220VAC on the 135 will it be converted to a 175??
Technically if the circuit board can sense the voltage is would work.
Greg
Greg
Take a look at the parts list in your owners manual. The machines have several components in them that are different. The most important component right off the top that is different is the transformer. The input and output power on the HH 135 is much lower then on the HH 175. So, the manufacturer can cut cost on the HH 135 by using a smaller transformer. More then likely, if you try to run your 120 volt HH 135 on a 230 volt power source all you will end up with is a very expensive boat anchor after you have totally fried the machine.
Dan wrote: (clip) the manufacturer can cut cost on the HH 135 by using a smaller transformer(clip) ^^^^^^^^^^^^^ Not only would it be a smaller transformer, but undoubtedly would have a different turn ratio. Welding at higher current, as the 175 does, does not require double the arc voltage, so what you need is more step-down, along with heavier wire in the secondary.
Greg, I suspect that the transformer is different. You can post this at Hobart's site and see what the Hobart/Miller guts say.
Hell, hook it up and try it. What's the worst that could happen?
Is your insurance current? oooooooooo bad pun ..........
Steve
No, you can't. If you look in the parts list, you'll find that different transformers, reactors, rectifiers, gas valves, fans, and control cards are required for the
230 volt 175 amp model. The *designs* are basically the same, but the parts are not.Gary
No, you can't. If you look in the parts list, you'll find that different transformers, reactors, rectifiers, gas valves, fans, and control cards are required for the
230 volt 175 amp model. The *designs* are basically the same, but the parts are not.Gary
Reactors - comes from Reactance - based on XL from Inductance and XC from Capacitance. X = |XL-XC| is the reactance of the circuit at any one time. Based on frequency.
XL = 2*pi*F*L (Hertz*Henry)
XC = 1/2*pi*F*C
Anytime there is a reflection of impedance there is a reflection of voltage and current.
Therefore, current is always somewhere between pure resistance and the resultant X value.
[ Gas Valves - didn't know they had tubes - oh - Gary is in "bell south country" so they are mechanical, not electronic (as in the U.K. :-) ]Martin
It's another term for a power inductor.
Gary
PolyTech Forum website is not affiliated with any of the manufacturers or service providers discussed here. All logos and trade names are the property of their respective owners.