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basic control problem

I have a basic question from ogata. i hope you know the answer.

consider the system defined by matrices: A=[0 1 0; 0 0 1; -6 -11 -6] B=[0; 0; 1] C=[c1 c2 c3]

Except for the obvious choice of c1=c2=c3, find an example set of c1, c2, c3 that will make the system unobservable??

To check the observability, i have formed observ.matrix Obsv=[C; CA; CA^2] the determinant of the "Obsv" must be nonzero. and it must be full rank. When i formed the "Obsv" matrix, such complicated matrix was become. Do you have any suggestions for c1, c2 and c3? Thank you

Reply to
temcon
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Homework?

Reply to
Tim Wescott

I'm studying for the exam.

Reply to
temcon

Can't you use software?

A = {{0, 1, 0}, {0, 0, 1}, {-6, -11, -6}}; cmat = {{c1, c2, c3}}; obsrv = {Flatten[cmat], Flatten[cmat . A], Flatten[cmat . MatrixPower[A,

2]]}; Det[obsrv]

c1^3 - 6*c1^2*c2 + 11*c1*c2^2 - 6*c2^3 + 14*c1^2*c3 - 48*c1*c2*c3 + 36*c2^2*c3 + 49*c1*c3^2 - 66*c2*c3^2 + 36*c3^3

Reduce[% == 0, {c1, c2, c3}]

c3 == -(c1/9) + c2/3 || c3 == -(c1/4) + c2/2 || c3 == -c1 + c2

--Nasser

Reply to
Nasser Abbasi

Ah. See my response to your original post, in a minute.

Reply to
Tim Wescott

If the system matrix were in diagonal form you'd have no problem, right? Because if the C matrix has a zero in it, then the corresponding mode (which only maps to one state) will be unobservable.

So one way you could do this is to find a similarity transformation to a diagonal form, zero out one or more columns in the C matrix, then transform the system back to the one you have.

(it worked for me, just like magic).

Reply to
Tim Wescott

Stretch my old ring out.

I Am Kirk Johnson. "Anal Stretching, Wrenching & Expanding Specialist"

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Reply to
Kirk Johnson

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