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## Homework Statement

Andy is 100 feet from Bob and Bob is 300 feet from Charlie and they are all facing the same direction on the same line.

They all begin to move in the same direction that they are facing at relative constant speeds.

In 6 minutes, Andy reaches Bob, and in another 6 minutes, Andy reaches Charlie.

How many minutes will it take for Bob to reach Charlie?

## Homework Equations

d = r * t

## The Attempt at a Solution

So I've drawn the initial problem like this:

Code:

```
A ---------- B ------------------------------ C
100 300
```

So A -> C = 400.

In 6 minutes, all A, B, and C will have moved a certain distance, so Andy's distance traveled = Bob's distance traveled + 100:

(R_A = Rate of Andy, R_B = Rate of Bob):

(R_A)(6) = 100 + (R_B)(6)

But Charlie has also traveled another 6 minutes worth of distance so I have to keep that in mind.

So in another 6 minutes, Since Andy was in the same position as Bob but is now up to Charlie (Charlie has traveled 12 minutes now also):

(R_A)(6+6) = (R_C)(12) + 400

I think. I'm not even sure if this is the correct distance traveled so far.

How do I find how far Bob traveled in 12 minutes?

(R_B)(12) = ???

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