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Battery and resistor. You measure the voltage across the battery and multiply it by the voltage across the shunt and the constant and you have power.
I'm confused about how I should interpret the data of the real life measurements I've taken. Power source is two 12v nominal batteries in series, which gives around 25v under load and 0.5v ripple.
Load: high frequency modulated sinewave UPS which generates sinewave using high frequency modulation then sends the output to step-up transformer to yield 120v rms.
The input current waveform is very variable and looks like this:
The voltage at battery was ~25v with 0.5v ripple under load, so I'm going to call that clean DC. DC ammeter reads about 3.2A, which means around 80W using simple math.
50KHz bandwidth power analyzer(should be enough to not overlook the high frequency component from sinewave synthesizer) reports 80.3W, which makes the simple math look right, but it reports 5.333A 133.32VA.The analyzer takes the square root of the sum of the squares to get the current, so sqrt(3.2ADC^2+4.26625AAC^2)=5.333A
Real question is, how much current through that shunt? 5.333A or
3.2A? What is the effect on the available capacity of battery? Do I calculate as if the load is 3.2A or 5.333A?