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Accelerometer constant displacement

I have a basic problem I hope that someone wouldn't mind helping me
with:
I'm using a shaker table and want to test at several frequencies, but
keep the same displacement.
Am I correct in thinking that I can say ma=kx and f=sqrt(k/m) (where m
is mass, a acceleration, k spring constant, f frequency and x
displacement) and so all I have to do to keep displacement constant is
keep (a/f^2) constant?
Reply to
pippaferguson
Loading thread data ...
For a mass bobbing on a spring, it is appropriate to equate the inertial force (ma) to the spring deflection force (kx).
Referring to a wiki entry:

you can see that acceleration when given as a function of time, a(t) =3D -A omega ^2 cos (omega t + phi) so for constant amplitude A -a(t) / omega^2 cos (omega t + phi) is constant
i.e amplitude is proportional to -a / f^2 as you say.
And frequency is PROPORTIONAL to sqrt(k/m)
Regards
BrianW
Reply to
Brian
On Thu, 11 Sep 2008 06:59:31 -0700 (PDT), Brian meant to write:
dunno where the extra garbage after the equals sign sprang from. Mr Gates, I suppose?
Brian W
Reply to
Brian Whatcott

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