Accelerometer constant displacement

I have a basic problem I hope that someone wouldn't mind helping me
with:
I'm using a shaker table and want to test at several frequencies, but
keep the same displacement.
Am I correct in thinking that I can say ma=kx and f=sqrt(k/m) (where m
is mass, a acceleration, k spring constant, f frequency and x
displacement) and so all I have to do to keep displacement constant is
keep (a/f^2) constant?
Reply to
pippaferguson
Loading thread data ...
For a mass bobbing on a spring, it is appropriate to equate the inertial force (ma) to the spring deflection force (kx).
Referring to a wiki entry:

you can see that acceleration when given as a function of time, a(t) =3D -A omega ^2 cos (omega t + phi) so for constant amplitude A -a(t) / omega^2 cos (omega t + phi) is constant
i.e amplitude is proportional to -a /
f^2 as you say.
And frequency is PROPORTIONAL to sqrt(k/m)
Regards
BrianW
Reply to
Brian
On Thu, 11 Sep 2008 06:59:31 -0700 (PDT), Brian meant to write:
dunno where the extra garbage after the equals sign sprang from. Mr Gates, I suppose?
Brian W
Reply to
Brian Whatcott

Site Timeline

PolyTech Forum website is not affiliated with any of the manufacturers or service providers discussed here. All logos and trade names are the property of their respective owners.