Hello everyone
While doing the project
"Rectangular Hollow Section beam calculator"
230724_ebbeam_rhs.html (-> 230720_ebbeam_rhs.php) which I mentioned here as thread "web-based beam calculator - RHS's only"
I needed a neat way to go from stress in a beam to its deflection. So came by this unexpected derivation.
- have you seen it before?
- is it known to be useful?
- any thoughts???
Stating again - if you think in terms of stress not force, you get an expression for beam deflection which has uses...
Regards, Rich Smith
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Derivation - deflection of symmetrical section in relation to stress
This expression for elastic deflection of a beam would be very useful "on-site" because everything you need to know can be obtained with a tape-measure (and a length of string!) to calculate the stress on a beam...
Symbols - all as familiarly used
"I" = Second Moment of Area "Z" = Section Modulus "M" = a Moment; a bending and/or turning force "F" = a force (in Newtons; N) "L" = length of the beam from supports to load (length beyond supports is irrelevant) "H" = height of symmetrical section in direction it is being bent "sigma" (Greek symbol) = stress (in N/m^2) "." == "*" meaning multiply
(1) M=FL/4 ("simple" beam)
(2) the massively significant equation which combines material property and geometric property... M=sigma.Z
noting "Z" = I/half-height for a *symmetrical* section Z=2I/H thus M=2.sigma.I/H
(3) and deflection d=F.L^3/48EI ("simple" beam - supported each end; load in the middle)
Restating and taking the derivation a step further: M=FL/4 => F=4M/L M=2.sigma.I/H d=FL^3/48EI
F=4M/L substituted into d=FL^3/48EI d=(4M/L).L^3/48EI
Cancelling L^-1 and L^3 to L^2
4/48=12
d=ML^2/12EI
From "fundamental" M=sigma.Z for a symmetrical section (eg. I-beam; circular, rectangular or square hollow section) we derive M=2.sigma.I/H
Substituting M=2.sigma.I/H into d=ML^2/12EI
(2.sigma.I/H)L^2/12EI=2.sigma.I.L^2/12EIH
"I" cross-cancels completely.
2/12=1/6
So... d=sigma.L^2/6EH
If you had a beam and stretch a string between its ends, a tape measure / rule in the middle between string and beam would measure the deflection. The tape measure also gives you the length of the beam and the height of the beam (or "depth")
eg. a 200x100x12RHS used on its major axis would be measured as having a height of 0.2m (200mm)...
as d=sigma.L^2/6EH then sigma=6EHd/L^2
So there with L, d and H given by your tape (and d needing your string). Steel always has an elastic modulus E of around 210GPA (210e9Pa) - so you know E already.
You can either deduce stress "sigma" from a measured deflection sigma=6EHd/L^2
or calculate the deflection you would get at the yield stress and go measure how much of the beam capacity is currently being used. d=sigma_yield.L^2/6EH You can take the nominal yield stress specification of the steel as its yield stress - so for an "S355" steel (which would be typical of an RHS) that would be 355MPa = 355e6Pa
As I said, this can only be used for symmetrical sections like I-beams and RHS's and cylindrical tubes. The "H" has that implication that the section must be symmetrical (you could not use this for eg. angle-iron ("L-shape") which is not symmetrical).