Table 8 of the NEC gives 61 strands for 750 Kcmil. An engineer
spec'ed flexible power cable that is UL listed with RHH insulation but
there are 1080 strands and the diameter is about 1/10th of an inch
larger than that listed for 61 strands in Table 8 Chapter 9 of the
NEC. The problem is regular 750 Kcmil lugs are too small. This
leaves two options use a 800 Kcmil lug which the contractor did or cut
a row of strands from the outside of the conductor where it goes into
the lug. So what is the solution? Also does anyone know the formula
for finding the diameter of a cable as a function of the number of
strands? This is an interesting math problem, but I have never seen
the solution.