Hah.. The challenge to *anyone* would be to wade through your muddle.
I am NOT going to do your work for you. Not giving a magnitude to your equations is either antagonistic or a cover-up.
Apparently for you, yes.
Your ongoing rudeness is duly noted.
and give you the results for the specific
At least I try to learn. Do you?
and indicate (as I already did) the resultant magnitude specifically.
You need to study Baranek, Kinsler, Small, Olson, and Colloms.
Not so. This is a smoke screen. The crux is disagreement on mechanical power, net force, and total damping resistance.
If you're nice to me, I may work up a *simplified* explanation of this to help you. :)
See? You give no magnitude, even on your first basic equation.
Now here *is* a challenge for you.. Give the magnitude of *all* terms in this and the magnitude of the resulting current and see how it matches *your* other current magnitudes of 0.232 amp and 0.244 amp. Take your time...
Many more equations follow without magnitudes. Take your time there as well...
The forward arrows indicate your original statement, but you have modified and restructured it. This exemplifies what I mean when referring to your muddle, if not deception. Please go back and work with your original copy. I have yet again included it at the end of the post.
The forward arrows indicate your original statement, but you have modified and restructured it. This exemplifies what I mean when referring to your muddle, if not deception. Please go back and work with your original copy. I have yet again included it at the end of the post.
33.75 =35.54 @71.76The forward arrows indicate your original statement, but you have modified and restructured it. This exemplifies what I mean when referring to your muddle, if not deception. Please go back and work with your ORIGINAL COPY. I have yet again included it at the end of the post.
The forward arrows indicate your original statement, but you have modified and restructured it. This exemplifies what I mean when referring to your muddle, if not deception. Please go back and work with your original copy. I have yet again included it at the end of the post.
The forward arrows indicate your original statement, but you have modified and restructured it. This exemplifies what I mean when referring to your muddle, if not deception. Please go back and work with your original copy. I have yet again included it at the end of the post.
Note it is also necessary for you to use your original and unmodified analysis.
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Here is your original analysis *yet again*. Why not make yourself a copy, it appears you need it. :)
Bill W.
E=1.41Volts, Re =5.78 ohms, Rms=2.23 Ns/m, M=0.0254 Kg, K=1/Cmt=3425 N/m Bl=7.17 N/A
Variables:
Eb =back emf (volts), *** magnitude = Fm =actual mechanical force (N), *** magnitude = V =velocity m/s, *** magnitude = Zm =actual mechanical impedance due to mechanical elements, *** magnitude =
w=2*pi*frequency ***magnitude =
Basic: I =(E-Eb)/Re *** magnitude = (1)
In steady state, Fm =ZmV (2) where Zm =Rms +j(wm-K/w) =sqrt (Rms^2 +(wM-K/w)^2) ***magnitude =
@ angle arctan (wm-K/w)/Rms ***magnitude =
Fm =BlI and Eb =BlV ***magnitude =
substituting in(1) Fm =(Bl)E/Re -(Bl)Eb/Re ***magnitude =
but this can be written as Fm =(Bl)E/Re -[(Bl)^2/Re]V ***magnitude =
Then (2) becomes (Bl)E/Re -[(Bl)^2/Re]V =ZmV ***magnitude = or (Bl)E/Re = [(Bl)^2/Re +Zm]V ***magnitude = (3)
While it is not necessary to know this, from a circuit point of view we actually have a voltage source consisting of E behind a resistance Re. The equivalent current source (see any circuit book) consistes of a current
E/Re ***magnitude =
shunted by
Re. E/Re ***magnitude =
is the "short circuit current (output voltage 0)(If the coil is held stationary then V=0 and the actual locked coil force is (Bl)E/Re). This current source when expressed in mechanical terms becomes a "force source"
F=(Bl)E/Re ***magnitude =
shunted by the equivalent mechanical resistance
(Bl)^2/Re. ***magnitude =
We can treat this element as a mechanical element as long as we remember it is not an actual mechanical element and as it is an internal part of the equivalent source, any power calculated in this element does not have a real world meaning in that it cannot be equated to any real mechanical or electrical loss. It's use is that a simpler model results. From the above we can find
V =[(Bl)E/Re]/[(Bl)^2/Re +Zm] ***magnitude = knowing V we can find Eb. ***magnitude =
Knowing V and Zm we can find the force
Fm =ZmV ***magnitude = From Fm we can find
I=Fm/(Bl) ***magnitude =
Now the results can be checked by calculating
Eb=E-RI ***magnitude =
and comparing it to the value found from V. The actual mechanical power is the real part of FV* where V* is the conjugate of V This becomes
FmV(pf) ***magnitude =
where pf = cos of phase ***magnitude =
difference between Fm and V ***magnitude =
Alternatively it can be written as
Pmec =|V|^2Rms ***magnitude =
The term
|V|^2 (Bl)^2/Re ***magnitude =
is, as I indicated above, isn't a true mechanical power and unfortuantely it isn't the
I^2Re ***magnitude =
loss either. It is simply an internal part of the "force source" That is the analysis part: now plug numbers Note magnitude @ angle form will be shown At 227.4 Hz
(Bl)E/Re =7.17*1.41/5.78 =1.75 N
w=2*pi*227.4 =1429 rad/sec
Zm =2.23 +j(0.0254*1429 -3425/1429) =2.23 +j33.75 =33.82 @86.22 degrees [mag 33.82]
(Bl)^2/Re =8.89 Ns/m
Then from (4)
1.75 (@0degrees reference) =(8.89 +2.23 +j33.75)V or 1.75 @0 =(11.12 +j33.75)V =(35.54 @71.76 )V [mag 35.54]V=1.75/(35.54 @ 71.76)=(1.75/35.54) @ -71.76 =0.0492 @ -71.76 [Mag:0.0492]
The corresponding
Eb =7.17*0.0492 =0.353 @ -71.76 volts [mag: 0.353]
Fm =ZmV ={33.82*0.0492) @ (86.22-71.76) =1.664 @ 14.46 [Mag: 1.664N]
I =Fm/Bl = (1.664/7.17) @ 14.46 =0.232 @ 14.46 [Mag: 0.232A]
Pmec =|V|^2Rms =((0.0492)^2)* 2.23 =0.0054 Watts. If the power factor approach is used then we have the angle between Fm and V is 86.22 degrees corresponding to the angle associated with
Zm cos 86.22 =0.066
Then Pmec =1.664*0.0492*0.066 =0.0054 W
To check that the I and Eb are correct
E-RI =1.41 -5.78*0.232 @14.46 =1.41 -(1.34 @14.46) =1.41-1.30-j0.335 =0.112-j0.335 =0.353 @ 71.6 degrees [Mag: 0.353 ]
This checks. If the Fm was wrong, then I would be wrong and this check would show an error. If I assume
F =1.75 (@0 as E is assumed at 0) ,
this corresponds to a current of 0.244 A @0
Then E-RI =1.41 -0.244*5.78= 0.00 !!!
This seems to differ from what Eb actually is - it is inconsistent - i.e something's wrong. This inconsistency does indicate that something is wrong with using this force as the actual mechanical force produced by the current in the coil. However, it is consistent with the 0 velocity or locked coil case which we appear to agree upon. ------------ If I do the same analysis at resonance then I will get
V=1.75/11.12 = 0.157 m/s
Eb =7.17*0.157 = 1.128 Volts
Fm =0.157*2.23 = 0.350 N
I =0.350/7.17 = 0.049 A
Eb=1.41-5.78*0.049 = 1.128 V checks
IF I use your force of 1.75 N as the actual mechanical force and the impedance at resonance of 11.12 Ns/m the velocity and Eb will be the same but the current will still be 0.244 A Frequency doesn't affect the current. !!!! Is this true? Obviously not. There is an inconsistency again. Again,at this current Eb =0 which implies the locked coil condition.