phase voltage

If the following equation gives the phase voltage for a PMAC when the phase current (Iph) is in phase with the back emf (Eph)
Vph = (Eph + Rs*Iph) + j*2*pi*frequency in hertz*Ls*Iph
how would equation change when the Iph is 180 degrees out of phase with the back emf?
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On 17/08/2013 7:33 AM, snipped-for-privacy@gmail.com wrote:

replace Iph by -Iph or + by -
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Don Kelly
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