| Sorry. But the insulation is very important. The current difference would | be the issue. The transformer would be designed to take the incoming | current it takes to run the exit light. If you put the load on the other | end.....would the windings be able to handle the current? | | I take it you are new to engineering. How many exit lights have you wired | up in your engineering job?
Of course the insulation is very important. What makes you think that I ever said it was not. I said it would not be the *ISSUE*. The reason is because merely running the transformer backwards puts the same voltage on each side that it expects.
The transformer designed for 277 volts on the primary and 120 volts on the secondary will have an insulation rating designed to handle each voltage in the respective places, as well as whatever maximum difference will exist anywhere in the winding or wiring terminal. Energizing the primary with
277 volts puts 277 volts where 277 volts is expected. Then 120 volts is induced where 120 volts is expected. Reversing it, you are putting 120 volts where 120 volts is expected, and 277 volts is induced where 277 volts is expected. As long as it is wired in reverse CORRECTLY, the insulation it has as designed will protect it in reverse.
If you were to energize the 120 volt side with 277 volts, then you have a problem. That will induce 640 volts on the 277 volt side, if it does not saturate the core first, and risk overvoltage on the insulation, if it doesn't burn out due to overcurrent first.
Since you are talking about stepping 120 volts up to 277, if you were to get it backwards, you could end up stepping 120 volts down to 52 volts. You'd get 18.75% of the wattage from 120 volt light bulbs that way.
Since both 120 volt and 277 volt circuits are typically configured with one hot wire and one grounded (neutral) wire, such a transformer may have the chassis grounded to the wire it expects is grounded. Back when there was not a separate ground wire, this was often done. Hopefully you won't have that unsafe situation.
The transformer _may_ be an autotransformer, meaning that the low voltage and high voltage share the same winding, and the circuits are not isolated. Since both 120 volt and 277 volt circuits are typically configured with one hot wire and one grounded (neutral) wire, this would not be a problem. But you may have only one neutral wire coming out for both sides. be sure your wiring is correctly reversed and correctly grounded.
Electricity is a hobby for me, not my job. So this means I probably know more about this than half the BSEE graduates out there (who mostly did not study power systems). The true power engineers who fully understand their field (not something a mere BSEE can always produce) are the ones to get real answers from.
|> | Some exit lights are feed with 277 and stepped down to 120. |> | I always wondered if I could feed one of those transformers with 120 and |> | hooked it to a 277V lay in light fixture would the insulation on the |> | transformer windings hold or cook? |>
|> The transformer has to have insulation to withstand at least the 277 volts |> that would be applied, wherever that 277 volts might be. Running it in |> reverse to step 120 volts up to 277 volts would be applying 277 volts in |> the same places 277 would be normally. So the insulation would not be an |> issue. |>
|> How the transformer is grounded might be an issue. |>
|> The capacity of the transformer (rated in VA or kVA) might be, depending |> on how much load you have. |>
|>
|> | Because I valued my job I never tried it but I bet it would have worked. |>
|> I take it this is not an electrical engineering job. |>
|> -- |> -------------------------------------------------------------------------- | --- |> | Phil Howard KA9WGN |
formatting link
|
formatting link
| |> | (first name) at ipal.net |
formatting link
|
formatting link
| |> -------------------------------------------------------------------------- | --- | |