The SI units for capacitance is C/V (coulomb / volts) and a coulomb is
A

So capacitance = (amps * seconds) / volts

If I want to know how much current a particular capacitor can supply for a determined amount of time, do I calculate it this way:

C: 6800uF V: 75v s: 5-second

therefore amps = 102mA for 5-seconds

Is this correct?

Another question: the voltage will decrease with time. How would I power say an IC chip for some amount of time since the voltage decreases over time? I have an old Sears stereo and the preset stations lose their memory if it's left off for a week or two.

When I was younger, I assumed a capacitor kept a chip charged, but doing the math, it would take a very large capacitor.

Thanks in advance.

***s (amps ***seconds).So capacitance = (amps * seconds) / volts

If I want to know how much current a particular capacitor can supply for a determined amount of time, do I calculate it this way:

C: 6800uF V: 75v s: 5-second

therefore amps = 102mA for 5-seconds

Is this correct?

Another question: the voltage will decrease with time. How would I power say an IC chip for some amount of time since the voltage decreases over time? I have an old Sears stereo and the preset stations lose their memory if it's left off for a week or two.

When I was younger, I assumed a capacitor kept a chip charged, but doing the math, it would take a very large capacitor.

Thanks in advance.