$36 All Copper 60 kW Fluidized Bed Radiator

The huge surface area and the high air flow rates through a conventional radiator are necessary because the heat transfer
coefficient between the tubing and air is so low.
Air-particle fluidization increases the air side HX coefficient by an order of magnitude thereby dramatically reducing materials costs, drag and pumping losses.
Installing a fluidized bed radiator would only require removing the fan, adding a blower and using the same water pump and hoses.
Assume the heat energy leaving the radiator is about equal to the mechanical energy leaving the crank, an 80 hp engine would need to sink 60 kW or 60 BTUs/sec. If ambient air is 100 F and the radiator averages 200 F then the delta T driving the heat transfer is about 100 F.
The heat transfer coefficient between the fluidized bed and coolant tubing is 500 BTUs/hr ft^2 F so a 100 F delta T => 50,000 BTUs/hr ft^2 or 14 BTUs/sec ft^2.
For 60 BTUs/sec the coolant tubing exposed to the bed only needs a surface area a little over 4 ft^2 or 600 in^2.
Assume the HX coefficient is about the same on the liquid side of the tube so double this area.
1/4" tubing has a circumference of about 1" so 100' of unfinned 1/4" tubing is all that is required to move 60kW in a fluidized bed radiator. 50' rolls of 1/4" cu tubing sell for $18 when used as a draw at plumbing supply stores. Aluminum would be much cheaper on a production run basis.
To keep the flow rate up and pumping losses down -- the coolant flow might be 20 gallons/min on the freeway -- the tubing should be cut into 1 or 2' lengths and parallel coiled inside of a 8" high 8" dia cardboard cylinder or box filled 1/3 with light particles. A 12 volt 200 watt blower -- somewhat larger than the ac blower -- is ducted to the bottom.
Hotter air would be rejected from the fluidized bed radiator because less air and lower pumping losses in the form of a big fan and high profile radiator drag are required to move 60 kW.
Bret Cahill
Add pictures here
<% if( /^image/.test(type) ){ %>
<% } %>
<%-name%>
Add image file
Upload

Add pictures here
<% if( /^image/.test(type) ){ %>
<% } %>
<%-name%>
Add image file
Upload

An energy balance on the air might provide some numbers:
Assume the air slows by half going through a conventional radiator:
highway speed = 80 ft/sec
100 ft^3/sec of air or 3.5 kg/sec
heat capacity is 0.24 cal/gm - K so adding 60 kW to 3.5 kg/sec of air increases the temp. 20 C.
A counter current flow fluidized bed radiator would pump out less air but at a higher temperature, maybe increasing the temperature to 30 - 40 C.
Bret Cahill
Add pictures here
<% if( /^image/.test(type) ){ %>
<% } %>
<%-name%>
Add image file
Upload
A conventional 60 kW radiator has 55 feet of 1" perimeter flat tubing.
The tubes have fins and the highway speed HX coefficient of air is higher but not nearly as high as the HX coefficient of a fluidized bed.
20' of 1/4" tubing should be plenty for a 60 kW fluidized bed radiator.
Think of the advantages:
No fan, just a small blower that uses 1/5 th power of the fan.
Very low profile = much less drag, several hp at highway speeds for a medium sized car.
The distributor keeps bugs away from the heat transfer surfaces, the outside of the tubing inside of the bed.
The inside of the tubing will never clog and if it does, just disconnect the hoses and run a wire through the tubing.
It's simpler cheaper lighter and more durable than a conventional radiator.
Bret Cahill
Add pictures here
<% if( /^image/.test(type) ){ %>
<% } %>
<%-name%>
Add image file
Upload

Polytechforum.com is a website by engineers for engineers. It is not affiliated with any of manufacturers or vendors discussed here. All logos and trade names are the property of their respective owners.