1) I read on the web what is inertia but never found how to calculate it.
2) If I have a motor with ball screw attach to the shaft. A metal sheet that weight 100 pound is attach to the ball scew nut. How can I determine how much torque the motor should deliver so I can have a angular speed of x rad/sec?
In basic terms, inertia is an indication of a certain body's resistance to rotate around a certain axis. Therefore it not only depends on the object's mass but also it's geometry (mass distribution).
How do we calculate it? Being "I" the inertia of a body, "In" the the n-th body's element's inertia and r the distance from the rotation axis to that body's element:
I = sum( In*(r^2) )
so, if a certain body is formed by 3 elements (inertia from body 1, 2 and 3 = I1, I2, I3) which are distanced from the axis of rotation (r1, r2, r3), then that body's inertia should be:
I = I1*r1*r1 + I2*r2*r2 + I3*r3*r3 For mor information you can look at
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or any book on newtonian mechanics.
Well, being "w" the angular velocity, "a" the angular acceleration and "t" the time, then we have:
w = a*t
And being "T" the applied torque, "I" the body's inertia and "a" the angular acceleration, we have:
T = I*a
Solving the torque equation in order of "a" and replacing it in the angular speed equation, we end up with:
w = (T/I)*t
...which says that if there is any torque applied on that body (the body's inertia is always nonzero), it is only a matter of time before that system reaches the wanted angular velocity.
Of course the problem isn't as simple as that. But without any additi> Basically, we need a little more information...
Correct, however the OP did distinguish between inertia and moment of inertia. You may have been correct that he/she did not know the difference. And it is unusual for the sleeve of a ball screw setup to be rotating... so moment of inertia wouldn't really apply.
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