I am currently building a piece of sculpture which uses a
Linear Actuator as a pulling mechanism. The one I have is fairly large with
a 12" rod when fully extended. The question I have is how much power
generally can these actuators provide as I require the device to pull around
12-14 lb of weight. The motor on the actuator is quite meaty. I was advised
by the guy who sold it to me that it can give "massive" output. Is this
true? Any advice is greatly appreciated. Thankyou
Rig it like you would have it in your sculpture. Orientation and load.
Cycle it a few hundred times. If you are satisfied, he did good.
Once the structure is proved out, the next concern will be allowing the
motor sufficient air flow to stay cool. Or keeping the cycle rate (how
many times a day you operate it) low enough that it can conduct to ambient
through your sculpture.
David A. Smith
I used to buy linear actuators with 36" stroke and rated at 1500 lb. The
motor was about 2-1/2" or 3" in dia and about 6" long (it moved slow as
molasses). So 12-14 lb with your actuator is certainly within the realm of
If you had a manufacturer and model number you could probably find all the
info you need on the internet.
On Sun, 9 May 2004 19:02:25 +0000 (UTC), "Simon Griffiths"
The mechanical power from a linear actuator will be about 40% of the
electrical power it consumes.
But I suspect you are interested in the force available.
Roughly estimate it like this:
Motor electrical power (from the plate)
times 0.4 = mechanical power (still in watts)
Mechanical power is force times speed
using force in newtons, speed in meters/second.
Here's a hypothetical example:
Linear actuator rated 24 volt 6 amps
Electrical power input = 24 X 6 watts = 144 watts
Mechanical power available is 0.4 X 144 watts = 58 watts
That could turn out to be, depending on the gearing:
58 newtons at 1 meter/second
232 newtons at 0.25 m/s or
580 newtons at 0.1 m/s
A newton of force is 2.2/9.8 pounds force = 0.22 lbs
A m/s of speed is 2.2 miles/hour
So the kind of force and speed product that 144 watts
of electrical input gets you are these:
58 X 0.22 lbs at 2.2 mph = 12.7 lb at 2.2 mph
50 lb at 1/2 mph
127 lb at 0.2 mph
Brian Whatcott Altus OK
Thanks for the explanation Brian...
I've been working on a small project to swivel a TV stand and was trying
to estimate the amperage requirements for my power supply. Your example
is just what I needed! :)
- Siddharth Vajirkar
Brian Whatcott wrote:
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