How do I calculate an amount of thermal expansion for a given shape if you
have Coefficient of Linear Thermal Expansion (7.2x105 in my case)
Thanks,
Alex
- posted 18 years ago
Linear Thermal Expansion
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- posted 18 years ago
Sorry, wrong coefficient. It is 1.1E-04
- posted 18 years ago
Isn't that pretty high? At least for metals...
Depends on the units... is the coeff. in cm/°C or inches/°F or..?
In any case it's a differential thing, if it's 5 inches at 20° and 5.1" at 50°...
Tim
-- In the immortal words of Ned Flanders: "No foot longs!" Website @
Depends on the units... is the coeff. in cm/°C or inches/°F or..?
In any case it's a differential thing, if it's 5 inches at 20° and 5.1" at 50°...
Tim
-- In the immortal words of Ned Flanders: "No foot longs!" Website @
formatting link
- posted 18 years ago
Think of your lump of plastic as expanding by 80 parts per million of
a dimension per degree C
Then a dimension of 50 length units if subject to 20 degrees C temp rise will expand by 50 X 80/1000000 X 20 = 0.08 so its dimension grows from 50 to 50.08 length units
You're welcome
Brian W
Then a dimension of 50 length units if subject to 20 degrees C temp rise will expand by 50 X 80/1000000 X 20 = 0.08 so its dimension grows from 50 to 50.08 length units
You're welcome
Brian W
- posted 18 years ago
length x coefficent x temp change
Alex wrote:
Alex wrote:
- posted 18 years ago
First you must know the units for the coefficient. ie... in/ft/deg. C
in/in/deg F. depending upon the material. The material expands
exactly as stated in the coefficient. Take the distance from point one
to point two and apply the coefficient to it.
John
John
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