Linear Thermal Expansion

How do I calculate an amount of thermal expansion for a given shape if you have Coefficient of Linear Thermal Expansion (7.2x105 in my case)

Thanks, Alex

Reply to
Loading thread data ...

Sorry, wrong coefficient. It is 1.1E-04

Reply to

Isn't that pretty high? At least for metals...

Depends on the units... is the coeff. in cm/°C or inches/°F or..?

In any case it's a differential thing, if it's 5 inches at 20° and 5.1" at 50°...


-- In the immortal words of Ned Flanders: "No foot longs!" Website @

formatting link

Reply to
Tim Williams

Think of your lump of plastic as expanding by 80 parts per million of a dimension per degree C

Then a dimension of 50 length units if subject to 20 degrees C temp rise will expand by

50 X 80/1000000 X 20 = 0.08 so its dimension grows from 50 to 50.08 length units

You're welcome

Brian W

Reply to
Brian Whatcott

Reply to

First you must know the units for the coefficient. ie... in/ft/deg. C in/in/deg F. depending upon the material. The material expands exactly as stated in the coefficient. Take the distance from point one to point two and apply the coefficient to it.


Reply to

Forget the math formulas. Use 1/16" per foot per 100 degrees F. An eight foot length can expand 1/2" if temperature moves from 0 to 100. If one end is fastened, it expands to the unfinished end. Don't forget--the width expands proportionately also. Humidity or moisture also plays a part. As an example, close tolerance nylon parts will seize if immersed.

Reply to

PolyTech Forum website is not affiliated with any of the manufacturers or service providers discussed here. All logos and trade names are the property of their respective owners.