After some web surfing, with HP being the same on a permanent magnet DC motor, is a lower RPM for the given HP better than a higher RPM for the same HP?
Motor A: 1HP, 90V, 2500 RPM, 10.7A 4.28A per 1,000 RPM Motor B: 1HP, 90V, 1750 RPM, 9.2A 5.26A per 1,000 RPM
Since I'm a recovering college graduate, does this mean more kick per RPM by the lower speed drive?
"Louis Ohland" wrote: (clip) does this mean more kick per RPM by the lower speed drive? ^^^^^^^^^^^^^^^^ I've never heard of anyone calculating amps per RPM, and I think that is because it is meaningless. First question: How do you know that both motors are developing 1 HP? Are the figures you listed measured or read off the nameplates? Of course, you get more torque at lower speed for a given horsepower. If the figures are accurate, then motor A is slightly more efficient than motor B.
Well, some manufacturers do not make finding their torque graphs readily available. The amps were off a manufacturer's website, but they are just summaries. No tables or graphs at all.
Efficiency aside, neglecting heat loss, wouldn't using a motor rated to deliver 1HP at a lower RPM be better?
A theoretically perfect DC motor has a 1:1 relationship between armature current and shaft torque, and a 1:1 relationship between armature voltage and speed. It is, in fact, the same relationship if you use the right units (Newtons, meters, volts, amps, radians and seconds) to do your calculation.
Real DC motors, unless they're horribly inefficient, don't stray too far from the theoretical -- so you can pretty much calculate the torque vs. current characteristic from the speed vs. voltage characteristic.
Define "better". The motor rated to deliver 1HP at the lower RPM is clearly capable of delivering more torque without overheating. Assuming that it's bearings and armature construction will stand up to the stress, you'll be able to get nearly that torque out of it at higher speeds (and voltages), but it'll probably be bigger.
If you need more than 1750 RPM and you don't want to mess with giving the motor higher than rated voltage, then the second motor is clearly worse. If you need more torque than the first motor can give and you'll always be operating at less than 1750 RPM, the second motor is clearly better. If neither of these two conditions hold, then you haven't given enough information.
If you're going to be gearing either of them down no matter what, and you haven't selected a gear ratio yet, then the speed and torque don't matter, so you need to look at efficiency (and heat generation), weight, and other factors that you haven't mentioned.
Certainly you must mean Volts per 1000 RPM. A common specification. At 52.6 volts per 1000 RPM, 92 volts will drive it to 1.75 K RPM.
Which motor is better? That is like asking which gear is better for a bicycle. Won't it depend on what you intend to use it for? One motor appears to be designed for more RPM, and less torque, (if they are really both 1 HSP motors) It appears that the specifications listed are somewhat ambiguous/ questionable. What are you planing to do? How many RPM do you really want?
Motor B has more torque at rated current. The A/RPM is meaningless, derived by dividing the rated full-load current by the rated RPM. One interesting observation, though, is that motor B is 16% more efficient than motor A, since they both deliver 1 HP at the same voltage, but B draws a lot less current.
maybe it will help to understand that horsepower is a measure of power, not force - torque is "force", RPM is "speed", power is the product, so to speak. one horsepower is 3300 ft-lbs per minute - e.g. a one horsepower motor can lift a 3300 pound weight (not mass) one foot in one minute, or it can lift a 1 pound weight about 2/3 of a mile in the same time.
This is only true of permanent magnet motors or shunt field motors operated with a fixed field voltage.
In the case of a perfect lossless SERIES field motor the shaft speed is directly proportionate to supply voltage AND inversely proportionate to supply current..
Because increase of supply current increases BOTH the field and the armature excitation, the shaft torque is proportional to current squared.
With regard to the original query, because the manufacturer quotes RPM/supply current, these are clearly series wound motors possibly intended for wheeled transport.
There is little to choose between them. The higher speed motor is likely to be slightly smaller and lighter than the lower speed machine. The lower speed machine is a bit more efficient and the lower speed and higher torque may be an advantage.
Neither machine is suitable if the main aim is constant speed with variable load.
If it is shunt or PM feild and enclosed frame of adequate horsepower at the correct rated speed, it's useable. The motor with the lower native speed for the same horsepower will be the stronger motor when used variable speed, as it will provide more torque at lower speeds than the highspeed motor will.
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