I'm trying to mill a conical hole using CNC. I'm having trouble programming a helical cut using and end mill. As it's sunday I can't pick up a tapered reamer to fit my needs.
Here's the geometry:
0.5" thick mild steel
0.5" diameter hole on top, 0.375" diameter at bottom on XY plane.
Here's the problem: Use a 3/8" ball mill to make this hole. The hole has been pre drilled.
Anyone have any G-Code samples to make this hole?
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J
J. R. Carroll
Here you go. Set the gage length carefully.
J
J. R. Carroll
"Eat at Sloppy Joes" wrote in message news: snipped-for-privacy@golden.net...
depending in the controll , use the macro funtion and have the path reduced by the "opisite and ajasin " per pass , ya know how we did it before "Cad-Cam" ??
B
Bill Roberto
Your going to have to do the work on this one. It will be tedious, but simple. (.5-.375)/2 = .0625. To figure out the angle take your side opposite .0625 and divide it by your adjacent .5 = .125, inverse tangent comes out to 7.125 degrees. Next you have to determine your stepover amount SQRT((Finish i.e. 63)*(8*tnr .1875))/1000000 = .0097, we'll round up to .01. Now calculate your side opposite (that is what you will subtract your radius by every time you step down in Z .01, .01*TAN7.125 = .00125. That's it, now get to work. You probably should calculate your start coordinates at about .02 above the work and your finish coordinates .02 below the work. Here is your first circle. (.00125*2)*2 = .005, (.505-.375)/2 = .065, your first coordinates will be Z.02 and a .065 radius, 2nd .065 - .00125 Z.01 and a radius of .06375. Good luck and have fun.
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