Anyone know how different grades of wet/dry sandpaper relate to the scratch depth they leave behind? I realize scratch depth must be very material specific but my interest would be mostly 6061 aluminum and mild steel. To phrase this question another way -- how much material would have to be removed to mirror polish out the scratches from 400,
There is no specific answer for this question. The reason is that any grade of paper contains a range of particle sizes both larger and smaller than the stated grade.
The size distribution conforms to the usual bell-shaped curve. I don't have any info on the width of the curve, but the FEPA grades(designated "P") have a narrower range of particle sizes than the US standard, CAMI grades. FEPA graded abrasives are becoming more and more common in the US.
There is also a difference in the grit size, for the same number, between the two grading systems. Above 220 grit, the difference in grit size becomes more pronounced as the numbers increase. For example, 320 = P400 and 600 = P1200 (approximately)
CAMI: Coated Abrasive Manufacturer's Institute (ANSI standard) FEPA: Federation of European Producers of Abrasives
Looks like 800 grit has avg dia of .00048". Assuming that you got all previous scratches out with the 800 grit, this would suggest that you'd need to remove somewhere between .00024" and .00048" of material to achieve a mirror polish.
On 30 Oct 2005 06:34:17 -0800, with neither quill nor qualm, "Dave" quickly quoth:
Your question is somewhat subjective, Dave. Dings and other scratches will determine the final material removal, not just optimal scratches from optimal grit sizes.
OTOH, does this help? It's the best chart I've seen for grit sizing.
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