I'm trying to calculate pipe size for a thin copper tube used to feed
a 10,000 psi pressure guage. The original was involved in an intense
fire and is totally blocked by carbonised hydraulic oil. It's o'd is
1/8" and it's i/d isn't easy to measure due to the blockage. Wall
thickness looks to be about 25 thou.

As I understand it the burst pressure of a pipe is given by:

P=(2t x S)/O

Where

P=Burst Pressure in PSI t= wall thickness in inches S is the tensile strength of the material in PSI O is the outer diameter of the pipe

I understand the tensile strength of copper to be about 70Mpa or 10,000 psi

So P = (2x0.025 x 10,0000)/0.125

So P = 4,000 psi

The pump puts out at least 8,000 psi and quite possibly the full 10,000 psi so what's going on - where am I going wrong as the pipe hadn't burst!

Also does anyone know a source of about a metre of thin (ie 1/8" o/d) but thick walled copper pipe?

AWEM

As I understand it the burst pressure of a pipe is given by:

P=(2t x S)/O

Where

P=Burst Pressure in PSI t= wall thickness in inches S is the tensile strength of the material in PSI O is the outer diameter of the pipe

I understand the tensile strength of copper to be about 70Mpa or 10,000 psi

So P = (2x0.025 x 10,0000)/0.125

So P = 4,000 psi

The pump puts out at least 8,000 psi and quite possibly the full 10,000 psi so what's going on - where am I going wrong as the pipe hadn't burst!

Also does anyone know a source of about a metre of thin (ie 1/8" o/d) but thick walled copper pipe?

AWEM