Hi all
I need some help if i might ask
I need to Model a chainwheel and drive its diameter by the pitch of each tooth.
the pitch is 12.5 mm or 0.492" for our american buddies
what i need to do is describe diameter as a result of the tooth pitch x the number of teeth
im puzzled this is probably really easy to some of you guys i can only describe the diameter of the circle using dimensions and not the circumference
any help
diameter = (number of teeth) x pitch / pi
That equation can come close, especially for large sprockets with a lot of teeth, here is a more accurate forumala: diameter=2*pitch*SIN((90-180/#_of_teeth)*ATN(1)/45)/SIN(360/ #_of_teeth*ATN(1)/45)
This equation includes the conversion to radians as solidworks requires (all SWX trig functions input/output radians)
I just answered a similar post on eng-tips.com. Is this the same poster???
Anyhoo, for a chain, look at the problem as a circle circumscribed about a polygon with "n" equal sides and length equal to pitch "p". Draw a line from the endpoints of one segment to the center, and calculate the radius by bisecting the resulting isoceles triangle.
The result: diameter = pitch / sin(180°/n)
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