Count me among those who think that $150 (or more) for a potentiometer, a switch, some wire, and an Amphenol connector is absurd. I've looked back through the archives and see that that for Lincoln this is a 10 K pot. I'm looking at the excreable excuse for a wiring diagram included with my manual (Ranger 250, K1725-1 - the first version of the Ranger
250) and I'm making the following guesses - I don't see the detailed information in the older posts I've looked at. This is a 6-pin Amphenol connector, pins ABCDEF:ABC are grouped as remote control, I'm guessing one end of potentiometer, wiper, other end of potentiometer, respectively.
DE are grouped as contactor, I'm guessing closing the switch turns welding on, opening it turns welding off, and that it need not be a hefty switch.
F is ground, seems obvious.
I'd just like to verify that "what I'm guessing" matches up with what other folks have done before I screw anything up by assuming I guessed right. I also don't find a complete consensus in the old posts regarding linear versus log (aka audio) pots for these controls. Even if I'm guessing correctly, it would be nice to know ahead of time whether wiper B at the A end of the pot is high amps or low amps.
I do stick welding with the machine. Eventually I'll probably get a TIG torch, as it has a TIG mode, though it is DC-only and lift-start (how will this limit what can be done?)
MIG with Lincoln accessories is another case of highway robbery, AFAICT, but a Readywelder seems possible eventually, given the presence of a CV mode.
The remote control would be useful now, as I have 50 foot (00) cables on it, and no wheels on it at present.