Drawing Parabolic Curve

Apr 25, 2008 5 Replies

Hello group,



I have a request from a customer to draw a specific parabola curve described as follows: Y=X squared / 4P. Where P = 6.



Anybody knows how to do that?



Thanks,



Jeannette


select a value for x calculate y X=-1 P=6 Y=(x*x)/(4*P) Y=(-1*-1)/(4*6) Y=1/24

X=0 P=6 Y=(x*x)/(4*P) Y=(0*0)/(4*6) Y=0/24 Y=0

X=1 P=6 Y=(x*x)/(4*P) Y=(1*1)/(4*6) Y=1/24

X=2 P=6 Y=(x*x)/(4*P) Y=(2*2)/(4*6) Y=4/24

so the command is draw single point enter the location if x=1 then 1,1/24 if x=2 then

2,4/24 if x=3 then 3,9/24 etc. connect the dots with polyline arcs. the closer the dots to each other the more accurate the curve.

Bob

or connect the dots with a spline

Hello,

There is a a little program (20 years old) to draw parabolic curves at

formatting link
- you can download the marvolisp.zip file, extract it into your AutoCAD's support directory and start the program with the command !(load "parabel.lsp") and then "parabel".

Martin

There is also a program called Z-grapher (freeware) which will do any functional, parametric or polar graph, and can export to a rastered format by copying and pasting. For this, I use Irfanview. ________________________________________ Everyone is a little krazy, but I am the kynge of krazy

KrazyKyngeKorny (Krazy, not stupid) =AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF= =AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF

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