74HC161 Question

Aug 14, 2008 0 Replies

I have a question about binary counters - the 74HC161 to be exact.


Today I was asked if I knew what a circuit does using this counter. The circuit had a high on all the inputs except the LSB. The output pin was Qc, and Qd fed back into the 'load' input.


I knew the counter started at 14 and reset on 0 but I couldn't describe its purpose.


It was then explained the circuit divides by 3 because there are only 3 counting states.


School only taught us how to load 0s and 1s to get the chip to count; we didn't focus on using them as frequency dividers.



Can someone explain what makes this a reconized divide by 3 circuit? What if I had the chip start at 4 and had another circuit reset the chip on 6? This would allow the chip to only count to 3, would it still divide by three?


I believe my confusion is from using the chip as a number loader/counter and not having much experience with chips as dividers. Maybe someone can also help me understand why this is confusing for me. :)


TIA


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