I think someone asked me how to correct power factor so here it is:
Correct each machine individually and fit the corection caps across the motor, that way you don't have caps connected to the supply without the matching machine which would make a leading pf all the time.
Before you can correct pf you need to be able to measure it, I believe you can buy cheap meters but have no experience of them, what you need is the pf, the current drawn and the voltage. Measure these with the machine operating in a representative manner as you can only correct accurately at one load.
Draw a right angled triangle and mark the hypotenuse with the current, the longer side with the current multiplied by the pf, and work out the third side using pythagoras. For example if you measure 10A and 0.8pf the triangle sides are 10, 8, 6 where 6A is the lagging component of the current.
Now you need a capacitor which passed this same current to 'cancel out' the inductive current, or more correctly cause it to circulate around the motor and capacitor rather than the grid. So just apply Ohms law i.e. the impedance of the capacitor Xc = U/I so assuming you measured 240V Xc =
240/6 = 40 Ohms.
Now the last step, the impedance of a capacitor Xc = 1/(2 PI f C) so rearranging C = 1/(2 PI f Xc) In the example C = 1/(2 x 3.14 x 50 x 40) = 80uF
That can be a single capacitor or a parallel combination where the total is
80uF, you must use motor RUN capacitor not motor start capacitors and they must be rated for the supply voltage. Of course if you are not completely confident in your abilities with wiring then get someone who is to do it.
There may be some rule of thumb for all this that I'm not aware of, but being an engineer I just get my pocket calculator out!.
Greg