| That's not the point here, though. The fact that the Astro 109 is | overcharging AT ALL is very worrisome.
To be fair, 12.75 v (or 4.25 volts/cell) is close enough to 4.2 volts that maybe they just decided to go a bit higher to get a bit more charge into the pack.
| A 3S pack "hot" off the 109 should read 12.60 Volts. That means that | at some point, it's detecting the 3S pack as a 4S.
I suspect that you're wrong here.
| If the 109 decided to stick with the 4S setting right to the end
And you think it changes it's mind mid-charge? No, it almost certainly detects it properly, and just thinks it's safe to go a bit over 4.2 volts/cell.
| Either this particular 109 is defective, or Wan's running at .5 Amps | over 1C caused the pack to be misdetected.
I doubt it's defective. This is probably by design.
| That would be insteresting. I'd like to see how he manages to up the | current without upping the voltage. Unless the cells' internal | resistances are REALLY low, there's no way to exceed 1C without | exceeding 4.2 Volts per cell. It's physics.
The internal resistances are really low. Especially if the cell is mostly discharged, if you take one of the modern 10C or 20C discharge rate cells, you could probably pump in 3C without exceeding 4.2 volts for a while. I'm not saying this would be smart, only that it's possible.
| BTW, charging at over 1C using contemporary | constant-voltage/constant-current charging technology will only make | a few minutes' difference in the charge time.
It would depend on your cell.
| Once the pack reaches 4.2 Volts per cell, the laws of physics | prevent the charger from maintaining the 1C current without raising | the voltage.
Actually, once the pack reaches 4.2 volts per cell, the laws of physics prevent the charger from charging at all without risking overcharging the cell -- because it's generally considered fully charged.
The charge voltage is *not* the same as the pack voltage while charging, and the difference will be the {internal resistance} * {the amperage}. The {internal resistance} will include the cell's internal resistance, the resistance of the wires and the connectors, but it can be calculated easily enough.
A charger could safely put put more than 4.2 volts into a LiPo cell as long as it stopped charging every few seconds to make sure that the cell itself wasn't above 4.2 volts yet. They could use the difference between the two voltages to calculate the internal resistance and use that. I don't know of any chargers that do this yet but it's certainly possible. It's also a tad more risky than the current setups, so I don't know if the extra speed is worth it.
| Since the charger can't raise the voltage without risking | catastrophic cell failure, the current naturally drops off. You only | gain a couple of minutes during the initial constant-current portion | of the charge cycle. Most of the cycle time is spent in the | constant-voltage mode
In my experience, most of the charge time for an almost fully discharged LiPo pack with my Triton charger is spent in the constant-current mode. It spends a few minutes ramping up at the beginning and around 10 more minutes ramping down at the end, but as long as the battery is mostly discharged when I start, over half of the time is spent at the charge rate (1C usually) that I told it to do.
Of course, the batteries I use the most are designed for high discharge rates -- up to 10C. So they would have low internal resistances, and would probably charge faster than batteries designed for slower charge rates. But even the other batteries I have spend most (60% or so) of their time at the full charge rate if almost fully discharged when I start.