Can some kind and clever soul tell me how many nauticle miles between the following GPS numbers:
Lon East 138 deg 48.889 Lat South 35 deg 38.012
If you could also explain the maths to arrive at the distance that would be helpful as well, or, perhaps some calculator on the web that can be used.
Thanks
DN
The distance is zero since you only defined one spot. You need two sets of lat and lon before you have a distance between them.
To find a distance between to points using Great Circle Navigation is as follows...
The great circle distance d between two points with coordinates {lat1,lon1} and {lat2,lon2} is given by:
d=acos(sin(lat1)*sin(lat2)+cos(lat1)*cos(lat2)*cos(lon1-lon2))A mathematically equivalent formula, which is less subject to rounding error for short distances is:
To CJ,
Are you also an (ex) seaman into RC??
Olivier
Am I missing something here?. Lon East. 138.48.889 and Lat South 35.38.012 seems to me to be a single point. Somewhere near Adelaide South Australia Should there be another set of Lat/Lon points?.
OOppps Let me start all over ;-)
distance from South 35 28.9 East 138.45
to
South 35 deg 38.012 East 138 deg 48.889
Must keep the cork on the fine Red methinks
DN
On 30 Sep 2005 05:43:48 -0700, snipped-for-privacy@iprimus.com.au wrote in :
Here is a google search:
Your Eastern figures (East 138.45) don't match the proper format.
Marty
Oliver,
No sir, but I get asked if I have been in the service allot lol. I am an Airforce brat so I guess some of that rubbed off (I am a full scale pilot though !) I have written software with these formula's and believe it or not, the first time in COBOL !!! All the other apps were VB and C.
CJ
Distance between 35 28'54"S 138 45' 0"E and 35 38' 1"S 138 48'53"E is
9.6658 nautical milesHi DN, As other will/have informed you, that Lat/Lon defines one point on the earth's surface. You'll need to select/define another point then you may go here
| 9.64853430988569 nautical miles.
Accurate enough for you? :)
That suggests an error of the order of 0.18 angstroms -- about 1/10 th of the size of a hydrogen atom :)
;-)
"CJ" wrote in news:Ooe%e.887$sL3.482 @newssvr13.news.prodigy.com:
oooh I'd never admit to COBOL!
I've had to write code that did similar things, but I did it all with vector math. It looks prettier than all that trig.
Well, I used to be ashamed of my COBOL expierence but after nearly 25 years of this computer stuff, I have fond memories of it...
CJ
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