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Impedances, Efforts and Flow in Passive Systems

While trying to design a controller for a passive system, I am a bit confused regarding the problem stated below:

All such functions are written like:

e(s) = Z(s).f(s) where e is effort, and f is flow, for example, a mechanical system would be described as

F(s) = Z(s).V(s) where F is force, and V is velocity.

I am getting confused that all this is in Laplace domain, what if I were to use this concept in time-domain? How would I translate a hybrid impedance transfer function from Laplace to time? Ofcourse I can take I.Laplace, but I feel I am missing something very basic.. Any help???

Thanks.

Tom

Reply to
Tom
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In addition to it.....

Lets say if I use Z(s) as a Simulink Block, could the inputs and outputs be treated as f(t) and v(t) instead of F(s) and V(s) or would I have to change something? I am really getting confused. What is the laplace transform of an input signal v(t) which is generated by a singnal generator in Simulink? ..... Help me....

Reply to
Tom

In Simulink a transfer function block Z(s) is turned into a time-domain differential equation and executed. Similarly a discrete-time H(z) is turned into a difference equation.

In Simulink the Laplace transform of an input signal is never taken -- everything stays in the time domain.

Reply to
Tim Wescott

Ohh okay. Tim Thank you very much for your explanation. Now it makes sense to me, I think. But just as a matter of discussion, so it means laplace domain is for design and analysis only, it is never used for simulation!! Am I right here?

-Tom

Tim Wescott wrote:

time-domain

Reply to
Tom

Reply to
Tim Wescott

Thanks Tim. Now I understand it. I visited your site too. It is very nice, esp. enjoyed your articles on z-transforms. Good work.

Reply to
Tom

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