Allen Bradley SLC503 PLC Analogue

I am new to analogue I/O's on PLC's. I have seen 4 to 20 mA inputs and the ladder programme that this represents (I think). The 4 ma is 3424 and the 20 mA is 16528 (IIRC) can check these numbers later. Can anyone tell me how we arrive at three thousand and odd and the sixteen thousand and odd. Is this some equivalent for the 4 to 20? What would this number be for say 12 mA? TIA

Reply to
BIGEYE
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0-20 mA is 0-16383. That's why 4 ma is 3277. You can figure out what any point is along the scale since it is a linear relationship.
Reply to
Bob Peterson

Thanks for that.

Reply to
BIGEYE

That's odd - I thought most AB SLC analog input modules were 14 bit resolution for current inputs . That is, they resolve 0-20 ma (range equals 20 ma) into

2^14 (16384) parts. Before any scaling, 0 ma should convert to the number 0 and 20 ma to the number 16383. Curious where the 16528 number came from?
Reply to
Perion

he is wrong about the numbers as I pointed out in a previous post, unless the thing is way off its calibration.

Reply to
Bob Peterson

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