# Ampere Turn in Electromagnet

I want to know ampere turn formula for using in electromagnet and the electromagnet will pickup iron piece from a distance which can be
100mm/200mm or any distance and design on 220 V DC.
How I know that the magnet are 220 volt dc or if the same will design on 110 V DC throu the ampere turn formula.
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I want to know ampere turn formula for using in electromagnet and the electromagnet will pickup iron piece from a distance which can be 100mm/200mm or any distance and design on 220 V DC.
How I know that the magnet are 220 volt dc or if the same will design on 110 V DC throu the ampere turn formula.
<% if( /^image/.test(type) ){ %>
<% } %>
<%-name%>
I want to know ampere turn formula for using in electromagnet and the electromagnet will pickup iron piece from a distance which can be 100mm/200mm or any distance and design on 220 V DC.
How I know that the magnet are 220 volt dc or if the same will design on 110 V DC throu the ampere turn formula.
<% if( /^image/.test(type) ){ %>
<% } %>
<%-name%>
I want to know ampere turn formula for using in electromagnet and the electromagnet will pickup iron piece from a distance which can be 100mm/200mm or any distance and design on 220 V DC.
How I know that the magnet are 220 volt dc or if the same will design on 110 V DC throu the ampere turn formula.
<% if( /^image/.test(type) ){ %>
<% } %>
<%-name%>
I want to know ampere turn formula for using in electromagnet and the electromagnet will pickup iron piece from a distance which can be 100mm/200mm or any distance and design on 220 V DC.
How I know that the magnet are 220 volt dc or if the same will design on 110 V DC throu the ampere turn formula.
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<%-name%>

Amperes x turns = ampere turns
Simple, isn't it?
John
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"John Nice" <johnDOTniceATbtinternetDOTcom> wrote in message

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I think he wants a nice "turn the crank without thinking" sort of design. Unknown core, large gaps, etc I would suggest that premji40 get professional help rather than formulae that it appears that he wouldn't understand.
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Don Kelly snipped-for-privacy@shawcross.ca
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Thanks
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Thanks your reply, the iron with little carbon contents and dimensions are:
================== - 60mm thick 750x750mm top plate | C|PPP|C | - 4Nos. 20mm thick side plates 530mm in height | C|PPP|C | | C|PPP|C | ----------------------------------- - bottom plate SS-304 5mm thick |P|- - - - 270 x 270mm x 530mm long pole | - C 3 or 4 coil in series | - operating 200mm weight pull 5kg iron piece max. - 220Volt DC Thank you Regards
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If your side plates are adequate, which doesn't appear to be the case. then you will have very little, if any lifting power because of the upper and lower plates (if magnetic- not indicated) . If they are not adequate, then you will have even less. You don't need a formula, you need someone who will design a device for you and it will be very expensive as your proposed minimum gap of 0.1 meter is huge. Given the application a device could be built (for any voltage-which is a secondary issue ) but may or may not be practical. Does what you have shown actually exist? Spend the money for a specific design based on required force at what distance (done), physical constraints as per volume etc and required operating voltage (220VDC) and possibly what it is for. Don't give a half design(sic) and expect someone to fix it for nothing.
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Don Kelly snipped-for-privacy@shawcross.ca