co2 pipw work flows

Jan 26, 2006 5 Replies

we are looking for some assistance in the form of pipe diameters, as a company we supply liquid carbon dioxide installations, as present we have a customer who is using liquid co2 fror cooling purpose, there present arrangement is from a small bulk supply which is 8 mtr away from the job this liquid is sent through a =BC pipe and then restricted to 1/8 stainless pipe for the last 12 inches



The customer has request a larger storage facility which is to be positioned 35 mtrs away from the job the orifice of 1/8 remains the same and the existing pipe of =BC also remains as this is a flexible which is required



We need to establish what the diameter of pipe from the storage vessel to the existing pipe would be, we think that =BD inch shed 80 should be sufficient.


Co2 will be at -17 and at 300 psi



=20



You advice on this matter would be appreciated



In my opinion, The smaller the pipe you can run would be better (cost efficient wise) as long as a larger volume is not needed at the end, so the 1/4 pipe would be most cost efficient basically. but also stainless steel would be the safest bet for less problems in the long run, but would be higher cost yet last longest. :)

Dear chrishamlett:

...

There are design requriements that may or may not apply based on low temperature design. What is the wall thickness and material of the 1/4" now?

Increasing the surface area of the piping increases heat loss to ambient. Increasing the diameter also serves to slow the velocity down, requiring that the flow stay in this now-warmer environment longer.

Personally, I'd hire a consultant. Someone that can keep your company out of litigation. If you don't, then I'd recommend you have your customer do it.

David A. Smith

Let's get a feel for this question by dealing with one that you may be more familiar with. If I run an electric hedge trimmer from a 25 ft electric extension, how would I choose a 100 ft extension lead?

The very first question you would probably ask is "What current does the hedge-trimmer take? Then, " how thick are the wires in the 25 ft extension?"

Given these data, you could probably deduce that if the voltage drop with the short extension was satisfactory, you would need about four times the wire cross-section in a 100 ft extension. Perhaps less than that even.

Now your actual question: we have the pressure, the temperature, but not the maximum flow rate desired. This is a problem. If the flow is negligible (unlikely, because you are selling them a bigger tank) then you could run 1/4 inch pipe all the way.

OK, lets suppose that you don't want to increase the head loss (pressure drop) due to steady flow over the longer route by more than

10% and let's suppose the Darcy equation applies - a factor for head loss is length times flow velocity squared / diameter.

Old pipe: length X V^2 / 0.25 New pipe:

4 X length X V^2/ Z X D

This amounts to reducing the flow velocity to one half its former value, giving 1/4 the head loss per unit length. This slower flow speed for equal flow rate needs a pipe diameter about root( 2) X 1/4 inch so a 1/2 inch pipe has got a chance!

This setup has the potential for causing a nasty accident - if a truck runs into it etc., etc. Are you fitting a flow snubber?

If you were in the US you might be well-advised to pay for an engineer's design. A lawyer for the plaintifs could search on the name "IGC company", for example. If he found your note on this group, he would be home and dry for a big payout!

Good Luck

Brian Whatcott Altus OK

Brian thanks for the reply, at present the customer uses the liquid out of a 200 ltr vessel which is 8 mtr a way from the job he uses 4 to

5 of these units per day hence the reason for a biger vessel so to ensure he does not run out. with respect to the flow to be honest this is it open for comment as the one eithth 1/8 pipe which is positioned at the point of use, is the factor which will determin the max flow is there any way we can establish this and we can then work back the dia for the extended pipe work ?

regards Chris

Well let's see: Torricelli found that the flow speed from a hole was the same as the speed that a particle would travel if dropped from the same height as the 'head' i.e. pressure. that is, V = sqrt( 2.g.H) H is head, g = 9,81 m/s/s

The pressure you give is 300 psi. Liquid CO2 has a density of

763 kg/ m^3 or a specific gravity of 0.763 say.... So the equivalent Head is roughly 300/15 X 10.13 /0.763 = 266 meters and the nozzle flow speed is about sqrt(2 9.81 266) = 72.2 m/s

But the nozzle diameter is 1/8 inch or 3.2 mm so its area is pi D^2/4 = 7.9E-6 m^2 and the flow rate is 72.2 X 7.9E-6 m^2 / s = 0.000570 cu meters/sec

Let's cross check: how long would a 200 liter tank last, if I got these numbers right?

200 liters is 0.2 cu meters so it would last 0.2 / 0.000570 seconds = 351 seconds or 5 or 6 minutes.

That's remarkably fast. Perhaps we had better model the pipe length as more than just an 1/8 in diameter hole.

In this case, instead of Torricelli's relation for exit speed, we use a variation V = sqrt(2.g.H / (1 + K) ) where K is a loss coefficient K = 4 f L / D where L = pipe length, D is pipe diam f is a friction factor say 0.008

K = 4 x 0.008 x 0.3 / 0.0032 = 3

Hmmmm... that halves the maximum flow - still goes pretty fast, uh?

In other words, just working out the maximum flow out of 12 inches of a 1/8 in diameter pipe overstates the maximum rate the customer uses.

Oh well...

Brian Whatcott Altus OK

Join the Discussion

Have something to add? Share your thoughts — no account required.

Didn't find your answer?

Ask the community — no account required