Need help with QPSK Demodulator

Jan 05, 2005 3 Replies

I've tried to realise the following circuit:



formatting link
from this article:
formatting link
to demod a QPSK signal. I've tried using an AD8347 (Evaluation Board), but i'm not able to retrieve the "terms at twice the rate of the oscillator". All I can get from the outputs are the difference between the RF and LO, both I and Q.



I'm using an (tunable) RF at 1.44GHz and LO at the same frequency. The LO is generated by ADF411xEB1. Even when I try to tune the RF as close to the LO, the "terms at twice the rate of the oscillator" never appears.



Is this becaues the range of AD8347 is 0.8-2.7GHz? So the doubler term,



2.88GHz, can never appear?

Has anyone tried any other components to realise this circuit?



Thanx in advance! kw


You don't need the sum frequency components for QPSK demodulation- so why would you want to "retrieve" them? And what are you using to "retrieve" them anyway?

Hi Fred

thanx fore replying!

I got the idea from this link:

formatting link
I can't get the waveform as shown in Figures 3 and 4 on the scope.I intend to pass this waveform thru a LPF (as suggested by the article) to recover the logic levels.

You mentioned that I don't need the sum frequency components (you meant the double freq component?) for demodulation, could you please explain the alternatives?

thanx again! kw

Problem solved.

thanks to all that have responded! =)

Join the Discussion

Have something to add? Share your thoughts — no account required.

Didn't find your answer?

Ask the community — no account required