Re: Calculating thermal conductivity

Hello,

> >I have a simple question. If I know the center temperature change of >some material, the ambient temperature, the heat transfer coeff, area, >thickness, etc... How can I calculate the surface temperature and/or k >value (I know how to get surface temperature with k or vice-versa). > >I tried a method for solving q=h*A*dT=k/dx*A* dT=m*Cp*dT/dt with dT = >(Ts + Tm)/2 where Ts = Surface temperature and Tm = Middle >temperature. This seems to give less than desirable results. Is there >a better way? > >Thanks.

It would be helpful to know if you're interested in one dimensional results. if k is the thermal conductivity, for example copper 384 watts per meter Kelvin cast iron 47.7 w/m.K

Materials vary in their temperature change, given a certain quantity of heating. For example, copper takes 380 joules per kilogram.Kelvin and the familiar example water, takes 4182 joules per kg.K or in the old units 1 cal per gm.K

?Can you find the material constants?

Brian Whatcott Altus OK

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Brian Whatcott
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Assuming a steady state heat conduction the following equations should suffice.

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R. Deepu

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