Guys/Gals, I'm building a miniature hit n miss and am just about finished with the flywheels (one on each end of the crankshaft). Material is cast iron. I have to cut in a keyway (internal to the crankshaft bore) that is tapered. According to the print, the taper is 1/8" per foot. Now, the outside diameter of the flywheel (finished size) is 6 inches. I was thinking that my "setup" would be to use the shaper head on my bridgeport. The "taper" is 1/8" per foot and I'm visualizing laying the flywheel flat on the milling table, then raising one edge of the flywheel .0625. My thinking, and I may be wrong, is that 1/8" per foot is .010416667 per inch but the flywheel OD is 6" so this number times 6 is .0625". The actual keyway is only 1/8" wide and 1/16" deep. The depth of the hub (clear through the bore is necessary) is 1" from side to side. Is my thinking correct on this? If I raise one side of the flywheel .0625, and use the shaper head to do a vertical stroke of 1" through the bore, will I end up with 1/8 per foot of taper in the keyway...? Thanks. Ken.
- posted
19 years ago