Patterned Holes

Hi I have a equally spaced linear pattern for a variable length part. How do I get the number of instances for the pattern to increase to match the increasing length of the part? I try to avoid eqautions, so many circular references; not sure equations would work here. Thanks gang

Reply to
Doug
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Doug,

Sounds like you need to use a design table. Don't have much experience with them myself, but maybe someone who does will chime in

Regards

Mark

Reply to
MM

Equations will work just fine. Circular references shouldn't be a problem if you know what you are doing. I have a pattern of holes that expands to fit the part. It is driven by an equation that calculates the number of instances along an edge. I have used this technique several time including some more complex problems with bolted joints. A design table will also work, but again, it is possible to have circular references.

Reply to
P.

Paul,

I think he wants to add and subtract holes, not just adjust the spacing. Don't know for sure, but I don't think you can do that with equations. (could be wrong, never tried it)

Regards

Mark

Reply to
MM

Certainly can. I have created a part that changes the number of instances of a hole based on the length of the part. You set the minimum spacing you will allow at the end of the part & the desired hole spacing, change the length of the part and rebuild it. It calculates the number of holes that will fit on the part, without going below your end threshold, and then centers the holes in the part. If, instead, you would prefer to have the starting distance constant, that would be an easy change.

Let me know if you want it.

WT

Reply to
Wayne Tiffany

You can I have done it. Double click the pattern feature and the quantities show blue in the graphics area. Add an equation to the apropriate quantity. Use the Dimension that drives the length and divide by the desired spacing. It will round up or down to the nearest integer. You can use an IIF statement to cause it to always round down.

Corey

Reply to
CS

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