This is one of the Frequently Asked Questions (FAQ) on the ZTC site.
<quote>
Assuming you are operating OO gauge then you will need to fit a power
booster, when your track gets to approximately 300 to 350 feet in total
length, to avoid data corruption due to the capacitive loading of the
track work. This figure includes all sidings and run around loops etc.
Data corruption usually manifests itself in a variety of ways all
related to erratic running. Locomotives are also slow to respond to
commands sent to them and in severe cases can even run away for no
apparent reason.
</quote>
My garden railway has 1200 feet of track, so according to this formula I
would need 4 boosters.
Also, remember that the decoder in a locomotive uses about 25 milliamps
when the loco is not running, so if you have a lot of parked locos they
will drain the available power somewhat. When they are running they can
take much more current than this, so in order to calculate how much
output you need you should add up the current requirement from the
maximum number of locos you are going to be running at once together
with those that are on the track but not running, and divide that by the
maximum output of your boosters, which will tell you how many boosters
you will need.
--
John Sullivan
OO in the garden http://www.yddraiggoch.demon.co.uk/railway/railway.html
add
consider what you are running and what lights and accessories are coming
from the same power source. This will determine whether you should wire in a
new power district.
Hope this helps,
Steve
The limitation before requiring boosters is the number of trains. Your DCC unit
will be limited to 2 or 3 amps while your trains will each draw 0,25 to 1 amp
each, even more if you run lighted coaches.
That could mean anywhere between 12 and 2 trains maximum.
If you're likely to have for example 3 heavy lighted trains in your main station
then you will need to add boosters and subdivide blocks but if you operate less
than 12 branchline locos on your layout you won't need boosters even if your
tracks run all the way around the local park.
That track around the perimeter of the park could be the answer!
I'd suggest 12 volts on the track and a hand held IR controller operating a
receiver
in the loco tender might be more suitable than DCC.
It depends on a lot of things - scale, bus wire size, number of
locomotives, and their current draw.
N-Trak in the US is suggesting (via an N-Trak Reccomended Practice: See
http://www.trainweb.org/nrmrc/dcc/rules.html ) that a layout have a booster
FEED to the busses in the middle of every 80 feet of track. Depending on
your exact physical configuration, this MAY not mean a booster for every
section. If the appropriate point can be reached by a bus feed with little
voltage drop, an additional booster may not be necessary. Particularly
with a home layout, simply feeding power from another channel of a power
manager device such as a Digitrax PM42 may be sufficient.
To this end, our N-Trak DCC RP strongly suggests 12 AWG wiring for the
bus. Yes, this is big wire. Most folks are using the 12 AWG zip cord now
sold in home hardware stores for low voltage landscape lighting
applications. At 12 volts, voltage drop over long runs of smaller wire
can be enough to make DCC unreliable, and this doesn't even take into
account the losses from connectors. (Remember that the total run of wire
is TWICE the distance from the booster - the distance out to the furthest
point AND BACK to the booster.
Good quality N scale locomotives from outfits like Kato and Atlas can
generally be relied on to draw .25 amp or less. (your mileage on
Grafar/Humbrol/Bachmann/whatever may vary!) This means a 5 amp booster can
run 20 locomotives at a time, or fewer if you're a fan of lighted
passenger cars. BTW, those passenger cars are one of the major design
considerations in that 80 foot (What, roughly 25 meters?) limit on power
districts.
More specifics about the layout you have or have planned would help.
Phil: As a long-time user of Zero-1 and now DCC, my observations:
1/ Although in theory, and in normal operation, there is only '1 circuit'
needed for dcc (/other command control systems), there is an adavantage in
being able to isolate sections for fault finding...
..if converting an existing, sectioned DC layout, to DCC, simply connect
the DCC controller in place of 1 existing DC controller, and switch it on
to (ALL) sections, at (ALL) times, unless there is a requirement (eg to
run more than 1 dc loco) to have the sections switched elsewhere.
(Oviously, any section of track must be switched to DCC, or OFF, or a DC
controller, but never both at any time - I originally bought 30 x 4 -way
mechanically interlocked (RadioBAndstyle egLW MW FM SW) switches to select
between any of 4 DC controllers - 1 per 'section')
If a short circuit occurs anywhere on the track, the ability to 'turn off'
sections will aid identification and rectification. An obvious error would
be a derailment or overunning a point set the wrong way (**see below).
2/ Reversing loops are NOT a problem, and are simply handled
automatically, by the 'appropriate box':
In our LGB, MTS layout, this is a small module located by the section,
which will automatically reverse the connection from the adjacent track /
distribution supply, as required.
For most OO implementations, the 'booster units' act as both a power
supply, and auto-reverser if required.
For my imminent rebuild, I am intending to use maybe 3 'power districts':
due partly to length (I was having to modify Zero-1 point modules as I
added the 25th-30-th modules, due to loading on 1 bus / circuit)
and partly for fault-finding / isolation, and also because I will NOW be
including reverse loop which I previously avided like the plague!
(And also coach lighting, and 'quiescent current' from lots of loco
modules just parked on the track - currenty about 0.5Amps for locos / lit
coaches only)
A 'Power District' is the term used to describe the area / amount of track
supplied from a single controller/booster/dcc base unit.
Typical output limits are 3A or 5A per unit (district) (some 10A available)
(>> **see below)
If running points off the system, and a short circuit occurs in a 'power
district', then point modules/decoders, fed from that power district will
be unable to operate.. as they will have no power... therefore the faulty
pint would have to be changed by hand!!!)
If running points off the system, the POWER to operate the points is
usually taken from a simple ac supply / cd discharge supply -- wheras on
Zero-1 this was ALSO from the track
(and why I ran separate busses for them)
rgds
Phil
--
Phil Spiegelhalter: snipped-for-privacy@fillin.co.uk
==== Technical Training for Broadcasters =====
No. Are you forgetting that the DCC signal ISN'T AC, but rather bipolar DC?
Frankly, I don't see what I said in my initial post that even bears on
that issue. Perhaps it's because you don't know what a "power manager" is?
One type is the Digitrax PM42. (see http://www.digitrax.com /, select
"Power Management" from the menu on the right, then "Digitrax Power
Management System-PM42" from the list of products). This lets you run as
many as 4 power districts from a single booster, at a rather large savings
over buying 4 boosters! As I said before, how you approach this problem
depends on a number of factors, including the physical size and
configuration of the layout in question. It is VERY possible to run a
layout with 500 feet of mainline track on a single booster, IF the
configuration of the layout is suitable and the bus wiring is up to it.
The referenced article above formed the basis for the DCC layout design at
the N Scale East show in Chantilly, Virginia, USA this past August. (It's
the SHORT version - the full DCC planning document ran to about 75 pages
in Adobe Acrobat format!) In that layout of well over five HUNDRED N-track
modules, about 5/8 of them were on the DCC red line route. (See
http://www.ntrak2004.org/caplimited2004_afterward.php for details)
The decision has already been made that for the next event, the _entire_
red line route (a full circuit of the layout) will run on DCC.
Phil: Offset? - only when in a braking section, or running a non-equipped
loco at other than zero speed (where the 'offset' is created by
controlling the ration of 1s and 0s sent so that the lowpass filtered (dc)
element becomes non-zero, and the loco moves. (The motor windings acting
as the filter, and doubling up as a loudspeaker - hence the buzz**)
**This seems to be how the old (DC) codar controllers added a steam
whistle to a loco back in the seventies.. a superimposed hf 'sound'.
The DCC Track waveform is a SHAPED*** datawaveform: it is therefore an ac
signal, and in normal use, has NO DC content (except for loco 0 as above).
The ALTERNATION is at the datarate: the transitions occurring at either of
2 spacings, representing a LOGIC ZERO or a LOGIC ONE - basic datarate
approx 10kHz.
This is A/ FULL WAVE RECTIFIED by the decoder, to provide DC power onboard
which is then regulated, as required, to control the motor speed (USUALLY
by pulse-width drive at frequencies from 50Hzish (old buzzy modules) to
32kHz (latest sound modules from ESU Loksound) - ehatever drive frequency
the decoder uses is totally independant of the datawaveform (and that is
where it is VERY different from the Zero-1 method, which was therefore
FIXED at a local mains frequency 50Hz or 60Hz (which would have been a big
problem in Japan, which uses both!!!)
This is B/ Read by the Microcontroller onboard the decoder (which was
powered bty the rectified track signal), and used to control the functions
and (pulse-width) drive to the motor.
*** Shaped: It is not 'TTL Logic' is shape, but rise-limited / slewed /
filtered to remove very high frequency components which would otherwise
interfere with other equipment.
It is not a Sinewave, either, but this is not a requirement for an 'ac'
waveform 8-)
OFFSET - Braking - this is one method used, and supported by some more
recent decoders, to initiate an automatic local (in section) braking mode,
with preprogrammed stopping distances etc - created by simply adding a
diode drop in one direction on the local track waveform - the assymetry is
then detected by the decoder, and applies the brake.
--
Phil Spiegelhalter: snipped-for-privacy@fillin.co.uk
==== Technical Training for Broadcasters =====
I couldn't help noticing at the time that the Zero-1 system was introduced very
shortly after series of articles on model railway control were published in
Wireless World. Does anyone know if the Hornby system was based on the
information in those articles or was it a completely different principle
altogether?
(kim)
At least with Digitrax and Lenz systems, it's not the "ratio" of ones to
zeros that's changed (which whould change the signal on the rails!), it is
achieved by "stretching" or lengthening the "0" signal on one rail or the
other so that a "perceived" voltage difference is applied to the the DC
motor. When "equal" zeros are present, the DC motor vibrates rapidly at a
very high frequency in equal amounts. (this is the "buzz) As the "zeros"
are "stretched", a bias develops in one direction, and the motor begins to
turn. The more the zeros are stretched, the faster the motor turns. The
pitch of the "buzz" also drops, and the volume decreases, as well.
However, this also slows down the transmission of data, and it can be a
_significant_ slowdown with several DCC locomotives on the rails and an
analog locomotive run at or near full throttle. This can be observed first
hand by setting up several MUd locomotives, then turning up an analog
locomotive to full throttle. (You don't need to actually have one on the
track). Turn the lights on, and reverse the direction of the consist. You
can see the delay as the directional lights change on the locomotives.
Turn down the analog throttle and compare the response time. This is why
most clubs do not allow operation of analog locomotive on DCC lines at
public shows or during operations.
Once again, it is NOT an AC signal. A true AC signal runs, for example,
from +12v to -12v on a single rail, in a sine wave. The DCC signal,
though, puts out 0 to +12v on one rail, and 0 to -12v on the other, using
a digital square wave. It's a seemingly minor but very significant
differance.
Phil: Wrong! - It is a bidirectional current signal, which with 2 wires is
the only way it can work - and that makes it 'ac' - place a diode in the
way to rectify it to dc, and it will stop working.
The only voltage measurement relevant is that between the two rails - and
these are alterantively positive and negative with respect to the other
rail,.... that AC.
Within a decoder, they are full wave rectified to produce 2 more voltage
rails - but those are internal to the decoder, and not relevant to this
discussion.
the polarity is reversing at abot 10kHz.
--
Phil Spiegelhalter: snipped-for-privacy@fillin.co.uk
==== Technical Training for Broadcasters =====
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