El=E8ctric fastness F_E works as the product of charges over their separation squarede kqq/ss. The accelerator's capacity, by capacitanse and inductanse, will say how fast that is.
Mhm, this is a good candidar for greater fieldly intensities at the input end:
Plug in the gradients at the above links.
-Aut
You don't ancall. 10^20 was the eV, so 10^20-9 =3D 10^11 would be gamma.
And as c is variant for two-bodied or many-bodied collisions, my old proof shew thas one /can/ reach v =3D c. Yawn.
-Aut
------------------ nice and in a shorty time ahead you will understand that the Gamma factor belongs actually to the energy side and not to the mass side as i indicated before and some time ahead you will present it as your or some anonymous insight ''from 80 years a go ''
ATB Y.Porat
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Once you get beyond 99% of c, it's easier to keep track of things in terms of energy or momentum rather than speed. While the speed is limited, the energy and momentum are not. Wake field accelerators are achieving energy transfer of about a GeV/m. A 60,000 mile run is about a 100,000,000 meter run, and so this corresponds to an energy of
100,000,000 GeV transfer in principle (though building a 60,000 mile long wave field accelerator would probably consume the GDP of the top 10 economic powers for a decade).For an electron accelerated, this corresponds to a relativistic gamma of 200 billion. The relationship between the fraction of the speed of light (beta) and gamma is beta=3Dsqrt[1 - 1/(gamma)^2]. In this case, this works out to a decimal point followed by 22 nines, approximately.
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