OT electrical question

Hi All, This is off-topic, but seasonal question, About 20 yrs ago I bought some "animated" Christmas tree baubles of eastern European origin, these contain a synchronous motor and were made to fit in replacement for a bulb in the now old style 20 lamp string of fairy lights. When bought originally I was wary of the safety of these things, but they did look very nice, ( also v cheap ) Being a safety conscious sort I thought that they would make a nice display running off a 12 Volt transformer - and as each bulb in a 20 light string being a 12 V bulb, also being a synchronous motor, obviously AC. I was therefore surprised when these things burnt out spectacularly in seconds on my bench when 12 Volt AC applied to them, (and I did check the applied voltage carefully).I destroyed three like that. Eventually I set the remaining baubles up in series with a 20 string lamp set, arranged with the lamps remote from kids reach and used this set up till the kids in due course grew up & departed. After a brief period of freedom we now entertain grandchildren at Christmas and I want to resurrect these motor driven baubles, again in a safe way. After all that preamble, I still do not understand why these things will not work when run off a 12 v transformer, There is only a synchronous motor inside them, exactly like in the old electric clocks, I dont want to blow any more up, but do want to have them out on display in a safe, and energy efficient way. So if anyone knows the answer to why I seem to need a dropper resistor instead of a 12 V. AC supply, or has a better idea of running these safely-feel free to post, Otherwise - Merry Christmas to all Mark G.

Reply to
Mark G
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Are they connected in series? So each bauble gets 12v / 20 = 0.6V each? or perhaps in groups of 4= 3v each?

I would get a megger on the connections between each bulb, and go from there.

Reply to
bigegg

Reply to
Mark G

In short, there's no reason to assume that every item in a series circuit is of the same voltage, the motor apparently has a lower impedance than one of the bulbs so has a lower voltage across it.

If you still have everything then connect the motor with the string of bulbs as intended, put a volt meter across any one of the bulbs and you will see about 12V, put the volt meter across the motor and you will see a smaller voltage, this is the voltage of supply you will need for the meter alone. Alternatively you can put an appropriate resistor in series with the 12V supply to drop the voltage, but to calculate this you'll also need to measure the current the motor and string of bulbs is taking and apply a bit of Ohms law.

Greg

Reply to
Greg

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