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The Creep response of a polymer corresponding to a load application for 100s

can be described by a Voight Model where the Elastic element = 2GPa, and the

Viscous element = 100 x10^09 Ns/m^2. If the Maxwell model has viscous

element = 200 x10^09 Ns/m^2

Find the value of the Maxwell elastic element.

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I have the solution below.....but I'm not sure that I'm correct. I have, for

Maxwell, Epsilon = (sigma

*/ E) + (sigma /*Viscosity).

I think it should be Epsilon = (sigma

*/ E) + (sigma^dot /*Viscosity). where

sigma^dot is 'stress rate' rather than stress..?

can anyone clarify for me?? If it is 'stress rate' rather than stress' how

do I calculate this - is it as a function of the time period??)

my working is this:

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Strain Rate for the Voight model is found from:

Epsilon = (Sigma / E) (1- exp (-E * t)/Viscosity))

Epsilon = (Sigma

*/ 2 x10^9) (0.864)*

Epsilon = Sigma * 0.432 x 10^-9 [eqn 1]

For the Maxwell model

Epsilon = (sigma /E) + (sigma

Epsilon = Sigma * 0.432 x 10^-9 [eqn 1]

For the Maxwell model

Epsilon = (sigma /

*/ Viscosity)*

Substituting eqn 1 gives

Sigma * 0.432 x 10^-9 = (sigma /E) + (sigma

Substituting eqn 1 gives

Sigma * 0.432 x 10^-9 = (sigma /

*/ Viscosity)*

Div thru by Sigma to give

0.432 x 10^-9 = (1 /E) + (1

Div thru by Sigma to give

0.432 x 10^-9 = (1 /

*/ Viscosity)*

0.432 x 10^-9 = (1 /E) + (1

0.432 x 10^-9 = (1 /

*/ 200 x10^9)*

0.432 x 10^-9 = (1 /E) + (5 x10^-12)

0.432 x 10^-9 = (1 /

1 / (0.432 x 10^-9 - 5 x10^-12) = E

E = 2.34 x10^9 Pa

E = 2.34 GPa