Hiya Terry,
>
> Terry Flynn wrote:
>
> > >
> > >
> > > Terry Flynn wrote:
> > >
> > > > >
> > > > >
> > > > > Terry Flynn wrote:
> > > > >
> > > > > > "Mark Newton" wrote in
message
> > > > > news: snipped-for-privacy@> > > > > > >
Big snip
> > I also don't accept that the friction of the bearings
> > > increases at a rate
> > > directly proportionate to the weight carried by it. For one
> > > thing, your 10 gram
> > > bogie does not have1/10th of the bearing area that my 100 gram > > > bogie has.
> >
> > Bearing area has little to do with our model bearings friction. >
> In that case, a 'pinpoint bearing' and a 'straight axle and bearing' would have
> much the same friction for the same load. That isn't correct.
A pin point bearing load is applied close to the tip. In effect we have an axle at this point with a small radius, only around 0.2mm as opposed to 1mm radius on an inside bearing. If the straight axle of the inside bearing was
0.2mm then your statement would be correct. A 0.2mm radius axle is not going to work for H0.
> > It has allot
> > to do
> > with wear. Friction force = Cofficent of friction x The force
perpendicular
> to the surface. A common emprical formula which has been used for a long
> > time by engineers. I am sure the science was done over 100 years ago to
> > support the formula. That'a a direct proportional relationship. > >
> > Inside bearings have a larger drag compared to pinpoint bearings because the
> > friction force acts at a larger radius, resulting in less mechanical > > advantage.
> >
> > > On a 1:50 my 4-6-0 gains an additional 2 grams shifted to the > > > drivers.
> > >
> >
> > Minimal compared to the large drag from the sprung bogie in my example using
> > scaled down proportion prototype axle loads.
>
> You've postulated a very light unsprung bogie vs a heavily sprung bogie. I did
> make the point that the force on the sprung bogie could be equal to the weight
> of the unsprung bogie.
That's fair enough, however if the spring force is this light, why have it? The point of the heavy spring was to simulate prototype axle loads thus be able to include some side control. As shown its a waste of time because tractive effort suffers to much.
If you can make a 10 gram unsprung bogie work then we could make a 5 gram bogie
> with 5 grams of springing and 5 grams added to the smokebox work or even a zero
> gram bogie with 10 grams of springing and 10 grams added to the smokebox. :-)
>
But why have the spring at all. The 5g bogie works fine. I don't have any 0g bogies.
>
> >
> > > > If I use a 4-4-0 as an example the results will be
> > > > worse. You need to increase the weight more than 52 % to match the > > tractive
> > > > effort of a lighter model using no sprung bogie and maintain the > > prototype
> > > > axle load proportion purely because of bogie bearing friction. An extra
> > 150g
> > > > simply won't fit.
> > >
> > > Of course it will, I have all that previously unused boiler
> > > and smokebox space,
> > > as well as utilizing the weight of the front half of the
> > > whitemetal
> > > boiler/smokebox which is, on your 4-4-0, lifting the rear
> > > drivers off the rails
> >
> > The total mass on the drivers is what counts. As long as the centre of
> > gravity is between the driving wheels, within reason there is no problem.
>
> If at the extreme you have 300 grams on the leading drivers and zero grams on
> the rear drivers, you will lose no tractive effort, but you have reduced your
> current collection to one axle and you have a loco that will not reliably
track
in reverse.
> Current collection and smooth tracking also count.
That's why I said within reason. My experience of H0 is you can have the centre of gravity within 5mm of an end axle before you get any problems.
> >
> >
> > >
> > > > Also the comparison
> > > > above assumes the model with no sprung bogie is only 300g total mass.
> > Make
> > > > the total mass the same for both options and the difference is larger
> > again,
> > > > more than 50% on the flat.
> > >
> > > I believe in adding as much weight as is possible! With both
> > > the 4-6-0 and more
> > > so with the 4-4-0 the inherent unbalanced weight is utilized. > > >
> >
> > You are still ignoring the facts about the increased drag from inside
> > bearings. The end
> > result is less tractive effort as the above examples show.
>
> Whatever weight you claim will work for your unsprung bogie will also work for a
> sprung bogie. In fact, the sprung bogie should work with considerably less
> downward force.
The practical solution is to discard the spring. One less part, one less adjustment. No need to add mass to the bogie.
> >
> >
> > > >
> > > > It is clear for H0 scale models using sprung bogies to simulate scaled
> > down
> > > > prototype axle loads results in under scale train lengths. > > >
> > > None of us can run scale train lengths. The friction of model > > > bearings doesn't
> > > scale, so where a light weight 0-6-0t (30 tonne) loco will
> > > easily move a 1000
> > > tonne train in a level yard, a model 0-6-0t won't even budge > > > a 60 wagon rake.
> >
> > Using my web page table and my wagon mass formula of 0.58g/mm a 1000
> > ton train is equal to 13.3 75 ton coal wagons. Wagon length is about 130mm,
> > train length is 1729mm. Train mass is 1003g. To move this train on flat
> > straight track requires a locomotive of only 100.3g mass. My white metal
> > NSW 18 can do it easily. My 0-6-0 whitemetal NSW 18 will move 60 4 wheel
> > wagons without much trouble. A small amount of wheel slip on starting could
> > be observed. It's mass is about 200g. I included a few bogie wagons to get
> > the full equivalent length. Train weight was not calculated. The test
> > includes going through 1 turnout and part of the train was on a slight up
> > hill grade around 1 in 100. It also pushed the train without any trouble.
> > In theory using the table on my web page it should be able to pull a train
> > of at least 2kg. How much mass is in your models will determine how many
> > wagons it equals.
>
> Stiction in model bearings is greater than rolling resistance. From my
> experiments, stiction in pinpoint bearings is about 150% rolling resistance.
I assume your term stiction is what I would call static friction and your term rolling resistance is what I call dynamic friction. Your results seem to match the difference in the friction values. I use the term rolling resistance to describe the force to pull a wagon, the total result of all factors. The chart on my web page is conservative, that it assumes the worst case, dynamic friction for driving wheels, static friction for the wagon bearings, the result is a conservative value. The above 0-6-0 I have pulls more than the theoretical case from my chart, which is what I would expect.
> >
> >
> > > I can weight my locos so that they will operate with a train
> > > that _represents_ a
> > > suitable prototype train without difficulty.
> > >
> > > OK, I'm off to weigh some bogies. :-)
> > >
> > > Regards,
> > > Greg.P.
> >
> > The above experiment proves I can pull full prototype length trains
> > appropriate to the
> > locomotive if
> > prototype curves and grades are used. I have compensated for the grades on
> > mainline curves thus maintaining full prototype mainline loads. My limit is
> > the siding lengths on my layout. If I can do it, so can you.
>
> I don't have the space available for prototypical curves or train lengths. My
> locos pull trains in proportion to those the most powerful loco can handle at
> scale speeds on my layout. As there are sharp curves in the hidden section and a
> steep gradient on the open section, this requires that locos be able to pull
> decent loads.
>
> Regards,
> Greg.P.
>